Regex pattern to get numbers from string

You can do it with a Perl one-liner:

perl -ne '$s+=$1 foreach /number of .*?: (\d+)/g; print $s'

Demo: https://ideone.com/8ghKE5

An awk version:

awk '{while(match($0,"number of [^:]+: ([[:digit:]]+)",a)){s+=a[1];$0=substr($0,RSTART+RLENGTH)}}END{print s}'

Demo: https://ideone.com/Hbccm9

Explanation:

• The while() loop sums up all numbers into variable s extracted with the help of the regex in match().
  • In the loop condition:
    • The match() function tries to find the pattern number of [^:]+: ([[:digit:]]+) in the current input string ($0) and stores capture groups (subpatterns in parenthesis - ([[:digit:]]+) in our case) in the array a.
    • The regex number of [^:]+: ([[:digit:]]+) matches substring "number of <something not containing ':'>: <sequence of digits>" and captures the <sequence of digits> (which is effectively a number we're looking for) into the capture group one.
  • In the loop body:
    • s+=a[1] adds to s the number which was captured in the group one by the regex in match()
    • $0=substr($0,RSTART+RLENGTH) removes from the input string $0 everything up to (and including) substring matched the pattern in the match() so that this match() would lookup further on the next iteration.
• The finalization block (END{...}) just prints the sum collected in s.