Is there a simpler way to iterate over multiple strings than a massive amount of nested for loops?
list = ['rst','uvw','xy']
for x in list[0]:
for y in list[1]:
for z in list[2]:
print x+y+z
rux
ruy
...
tvx
tvy
twx
twy
Example list I really want to avoid typing writing loops for:
list = ['rst','uvw','xy','awfg22','xayx','1bbc1','thij','bob','thisistomuch']
You need itertools.product:
import itertools
list = ['rst','uvw','xy','awfg22','xayx','1bbc1','thij','bob','thisistomuch']
for x in itertools.product(*list):
print(''.join(x))
product returns all possible tuples of elements from iterators it gets. So
itertools.product('ab', 'cd')
will return a generator, yielding ('a', 'c'), ('a', 'd'), ('b', 'c'), ('b', 'd')
You are looking for the product function from itertools:
import itertools
lst = ['rst','uvw','xy']
[''.join(s) for s in itertools.product(*lst)]
# ['rux',
# 'ruy',
# 'rvx',
# 'rvy',
# 'rwx',
# ...
# 'twx',
# 'twy']
Another way? Definitely. Simpler? Maybe not...
I'm guessing it's because you don't necessarily know how many strings you'll have in your list.
What about: sl = ['abc','mno','xyz']
def strCombo(l,s=''):
if(len(l)==0):
return s
elif(len(l)==1):
return [(s+x) for x in l[0]]
else:
return [strCombo(l[1:],(s+x)) for x in l[0]]
final = []
for x in strCombo(sl)[0]:
final = final + x