How to initialize array of custom class objects? [duplicate]

Question

It sounds easy but i've been trying to do it for quite sometime, I want to initialize my custom class object array using curly braces

Here is the failed example:

class:

class Tranforminfo{
        int left;
        int top;
        int right;
        int bottom;
        float rorate;

        public Tranforminfo(int left, int top, int right, int bottom, float rorate) {
            this.left = left;
            this.top = top;
            this.right = right;
            this.bottom = bottom;
            this.rorate = rorate;
        }
    }

Usage: (not correct)

// attempt 1 
Tranforminfo somedamn = new Tranforminfo[]{(1,2,3,4,5),(6,4,3,5,6)};

// attempt 2
Tranforminfo somedamn = new Tranforminfo[]{{1,2,3,4,5},{6,4,3,5,6}};

// attempt 3
Tranforminfo somedamn = new Tranforminfo[]((1,2,3,4,5),(6,4,3,5,6));

No luck so far help appreciated , i am coding in android(JAVA)

Read our lovely new Docs page stackoverflow.com/documentation/java/99/arrays/404/…... — Tunaki
– Tunaki, Commented Aug 14, 2016 at 19:54
attempt 1 is the closest: Tranforminfo[] somedamn = new Tranforminfo[]{new Tranforminfo(1,2,3,4,5), new Tranforminfo(6,4,3,5,6)};. (But you can drop the new Tranforminfo[] too). — Andy Turner
– Andy Turner, Commented Aug 14, 2016 at 19:55
i have to write new for each one ? that's strange C/C++ would have allowed this — Zulqurnain Jutt
– Zulqurnain Jutt, Commented Aug 14, 2016 at 19:56
Java and C/C++ are not the same language; don't expect the same features. — Andy Turner
– Andy Turner, Commented Aug 14, 2016 at 19:57

jisecayeyo · Accepted Answer · 2016-08-14 20:14:06Z

10

There is some ways to do it:

Transforminfo[] somedamn = 
    new Transforminfo[] { new Transforminfo(1,2,3,4,5),
                          new Transforminfo(6,4,3,5,6) };
Transforminfo[] somedamn = 
    { new Transforminfo(1,2,3,4,5), new Transforminfo(6,4,3,5,6) };

First you create Transforminfo array link, then add new Transforminfo elements into.

It's like Integer []array = {1, 2, 3}, but you have to use constructor to create Transforminfo elements.

One more example to understand array of object creating. All way is equal.

String array[] = { new String("str1"), new String("str2") };
String[] array = { new String("str1"), new String("str2") };
String array[] = new String[] { new String("str1"), new String("str2") };
String[] array = new String[] { new String("str1"), new String("str2") };

edited Aug 14, 2016 at 20:14

answered Aug 14, 2016 at 20:01

jisecayeyo

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1 Comment

Arjan Over a year ago

Strings are really odd beasts to use as an example here. ... { new String("str1"), ... as in your examples makes a new object in the heap but String[] array = { "str1", "str2" }; would use the string constant pool

Regedit · Accepted Answer · 2016-08-14 20:02:12Z

3

Transforminfo[] somedamn = {new Transforminfo(1,2,3,4,5), new Transforminfo(1,2,3,4,5)};

Transforminfo[] is creating a link to an Array of Transforminfo and with the {...} you create the actual Array (a special java syntax and actually the shortest one)

What you did was: You created a link to a Transforminfo Object and tried to set this link to an Array Object

edited Aug 14, 2016 at 20:02

answered Aug 14, 2016 at 19:57

Regedit

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1 Comment

Tunaki Over a year ago

A little more explanation wouldn't go amiss. What does this do and how does it do it?

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