Deserialize a JSON Array in c# with Newtonsoft

Question

I just try to deserialize an Json array but it doesn't work. I can read the following message in the output box :

" Newtonsoft.Json.JsonReaderException: Invalid JavaScript property identifier character: '. Path '[0]', line 2, position 37."

My code :

using System;
using Android.App;
using Android.Content;
using Android.Runtime;
using Android.Views;
using Android.Widget;
using Android.OS;
using Newtonsoft;
using System.Collections.Generic;
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;

namespace JsonTest
{
    [Activity(Label = "JsonTest", MainLauncher = true, Icon = "@drawable/icon")]
    public class MainActivity : Activity
    {

        protected override void OnCreate(Bundle bundle)
        {
            base.OnCreate(bundle);

            // Set our view from the "main" layout resource
            SetContentView(Resource.Layout.Main);

            // Get our button from the layout resource,
            // and attach an event to it
            Button button = FindViewById<Button>(Resource.Id.MyButton);

            button.Click += delegate
            {
                string json = @"[{
                                   id': '1',
                                   'nom': 'zooz',
                                   'prenom': 'Jack'                                 
                                 }, {
                                   'id': '2',
                                   'nom': 'toto',
                                   'prenom': 'Blaireau'                                 
                                 }]";

                var a = JsonConvert.DeserializeObject<List<Person>>(json);
                //JArray b = JArray.Parse(json);


               Console.WriteLine(a);
                // [email protected]};
            };
        }

        public class Account
        {
            public string id { get; set; }
            public string nom { get; set; }
            public string prenom { get; set; }
        }

        public class Person
        {
            public Account person;
        }


    }
}

Thank for your help.

A single quote (') seems to be missing in 'id':'1'

Halis S.
– Halis S.

2016-08-23 15:07:17 +00:00
Commented Aug 23, 2016 at 15:07 — Halis S.
– Halis S., Commented Aug 23, 2016 at 15:07
Thanks you. It was a stupid error.

Matthaousse
– Matthaousse

2016-08-23 15:41:19 +00:00
Commented Aug 23, 2016 at 15:41 — Matthaousse
– Matthaousse, Commented Aug 23, 2016 at 15:41

Mostafiz · Accepted Answer · 2016-08-23 15:08:22Z

2

A single quote missing in id

string json = @"[{
                   'id': '1',
                   'nom': 'zooz',
                   'prenom': 'Jack'                                 
                  }, 
                  {
                    'id': '2',
                    'nom': 'toto',
                    'prenom': 'Blaireau'                                 
                  }]";

also the model Person need to be hold List of Account

 public class Person
  {
      public List<Account> person;
  }

answered Aug 23, 2016 at 15:08

Mostafiz

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Comments

rmc00 · Accepted Answer · 2016-08-23 15:31:30Z

0

Your JSON is missing a single quote, and it also corresponds to a List<Account> rather than List<Person>. This JSON should deserialize successfully into List

[{ 'person':{
   'id': '1',
   'nom': 'zooz',
   'prenom': 'Jack'                                 
 }}, { 'person': {
   'id': '2',
   'nom': 'toto',
   'prenom': 'Blaireau'                                 
 }}]

edited Aug 23, 2016 at 15:31

answered Aug 23, 2016 at 15:08

rmc00

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3 Comments

Mostafiz Over a year ago

for that case need another model class which hold list of person

rmc00 Over a year ago

The account class has the id, nom, and prenom properties like the JSON. The person class has a single property named person, which is an instance of that account class. So to deserialize as a List<Person>, you have to add that person property which has the JSON structure of an account. Other option is to deserialize as a List<Account>. But there is no need for another model class as far as I can see...

Mostafiz Over a year ago

thats true, but take a look at your json in answer

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