PHP - copy an array does not work

Question

I have an array:

print_r($resultArray);

Array
(
    [AB34] => Array
        (
            [a] => 13
            [b] => 10
            [c] => 3
            [d] => 88
            [e] => 73
        )
    ...
)

And I want to copy this array into another one:

$resArray[] = $resultArray;
print_r($resArray);

->

Array
(
    [0] => 1
)

So the new array $resArray does not have the content of $resultArray. What needed to be done to solve this?

Best Regards.

UPDATE: I have to copy the $resultArray into $resArray (that's an easy example), because $resultArray will change and I need the data in a $resArray with index, so $resArray[0] the first $resultArray, $resArray[1] the second full value of the $resultArray, ... Some code (only a simple example!):

$resArray[0] = $resultArray;
... calculations on $resultArray ...
$resArray[1] = $resultArray;
... calculations on $resultArray ...
$resArray[2] = $resultArray;
... calculations on $resultArray ...

Michael Clerx · Accepted Answer · 2010-10-12 08:46:52Z

I can only guess you have a small syntax error somewhere. My testcase works as expected:

$resultArray = array(
    'AB34' => array(
        'a' => 13,
        'b' => 10,
        'c' => 3,
        'd' => 88,
        'e' => 73
    )
);

echo '<pre>';
echo "Printing \$resultArray\n";
print_r($resultArray);

$resArray[] = $resultArray;
$resArray[] = $resultArray;
$resArray[0]['AB34']['c'] = 'Penguins are neat';

echo "\n\nPrinting \$resArray\n";
print_r($resArray);

Returns

Printing $resultArray
Array
(
    [AB34] => Array
        (
            [a] => 13
            [b] => 10
            [c] => 3
            [d] => 88
            [e] => 73
        )

)


Printing $resArray
Array
(
    [0] => Array
        (
            [AB34] => Array
                (
                    [a] => 13
                    [b] => 10
                    [c] => Penguins are neat
                    [d] => 88
                    [e] => 73
                )

        )

    [1] => Array
        (
            [AB34] => Array
                (
                    [a] => 13
                    [b] => 10
                    [c] => 3
                    [d] => 88
                    [e] => 73
                )

        )

)

Narf · Accepted Answer · 2010-10-12 07:52:55Z

1

$resArray = $resultArray;

... also use print_r($var, TRUE); in order to get the full contents of the variable.

answered Oct 12, 2010 at 7:52

Narf

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3 Comments

oezi Over a year ago

1. some explanation never hurts // 2. this is one failure in the code of Tim, but dosn't tell why he's only getting a "1"

Tim Over a year ago

I updated my first post. I have to put several $resultArray's into $resArray, so I will need the index.

Matěj G. Over a year ago

Err, php.net/print_r – the second parameter tells it to return output of the function instead of printing it.

Sarfraz · Accepted Answer · 2010-10-12 07:54:12Z

1

Try without brackets like this:

$resArray = $resultArray;
print_r($resArray);

answered Oct 12, 2010 at 7:54

Sarfraz

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1 Comment

Tim Over a year ago

I updated my first post. I have to put several $resultArray's into $resArray, so I will need the index.

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