replacing array index value

Question

I have an array in which there are users values are stored that will be sent to execute(); function for mysqli query. So, I want the index values to be replaced.

Now what I have done here is used str_replace(); function to do so within foreach loop but the problem is that how I will get the updated array?

$fields = array(
 'field_id' => '123', 
 'field_name' => 'test_name' 
);

foreach ($fields as $key => $field) {
  $val  = str_replace($key, $key, ':'.$key);
  $data = array();
  $data[$val] = $field;
} 

//I only got the value for the last index 1st is not there
print_r($data);

//output which I am expecting will be the following
$fields = array(
  ':field_id' => '123',
  ':field_name' => 'test_name'
);

Please let me know if any one could help me out

I don't think str_replace will do what you want. Why don't u just do sth like this: $fields[':'.$key] = $field; unset $fields[$key]; — Ann-Sophie Angermüller
– Ann-Sophie Angermüller, Commented Aug 26, 2016 at 9:34
str_replace(searchterm, replacement, subject), you're doing it wrong, probably ... also, you should create the empty array before the loop, not inside, or only the last entry will remain ... — Jakumi
– Jakumi, Commented Aug 26, 2016 at 9:36
Use the Version from Object Manipulator. It's an even cleaner Solution. — Ann-Sophie Angermüller
– Ann-Sophie Angermüller, Commented Aug 26, 2016 at 9:37

Indrasis Datta · Accepted Answer · 2016-08-26 09:47:12Z

3

The objective is to prepend each key with a colon (:).

This can be achieved by looping through the main array, modifying each key and filling these key value pairs in $newArray.

We can loop through $fields, fetch each key and prepend it with ':', and make this the key of our $newArray. i.e field_id becomes :field_id, field_name becomes :field_name.. and so on.

The values are copied from $fields and put in $newArray as it is.

$newArray = array();
foreach ($fields as $key => $field) {
     $newArray[':'.$key] = $field;
}

edited Aug 26, 2016 at 9:47

answered Aug 26, 2016 at 9:36

Indrasis Datta

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4 Comments

Mark Alan Over a year ago

Thank You it worked for me but I did not understood what actually you did here

Mark Alan Over a year ago

okay so when ever we define an array like $a = array(); what ever we store in $a will be converted to array automatically

Mark Alan Over a year ago

Thank you very much for the solutions and explanations

Indrasis Datta Over a year ago

Actually, that syntax would mean we are declaring a new variable of type array. If a variable with a same name was already created earlier, they would be reset as a blank array. So, it's better to use this syntax for these kinds of operations.

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