Initialize a 2D string array and print it

Question

I'm learning C for fun and I'm trying to make a program that creates a array of strings. I'm trying this right now:

char str[2][10];
strcpy(str[0], "foo");
strcpy(str[1], "bar");
printf("%d \n",str[0]);
printf("%d \n",str[1]);

But my printf returns only some numbers, and I would like it to display foo and bar. I've been reading about and I think that it is displaying a pointer to my strings. What am I doing wrong?

You might want to spend a little time looking at the printf and format string documentation. — lurker
– lurker, Commented Aug 27, 2016 at 15:18
You have a 1D-string array, which in fact is a 2D-char array. (I adjusted the title accordingly) — alk
– alk, Commented Aug 27, 2016 at 15:25
Sorry for bothering you guys with such na amateur mistake. I edited the title to make it match with the text. Thank you for the answers! — Rafael Kehl
– Rafael Kehl, Commented Aug 27, 2016 at 16:11

Marievi · Accepted Answer · 2016-08-27 15:22:42Z

6

You are printing using the format %d, which is used to print an int. Modify your code to :

printf("%s\n", str[0]);
printf("%s\n", str[1]);

See this link for more information on the specifiers' format for printf.

edited Aug 27, 2016 at 15:22

answered Aug 27, 2016 at 15:16

Marievi

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