I would like to open and work with a file with Python however I would like to use Windows %systemdrive% when referring to a file instead of full path.
This piece of code works:
if not os.path.isfile('C:\\Work\\test\sample.txt'):
This does not:
if not os.path.isfile('%systemdrive%\\Work\\test\\sample.txt'):
Any idea? Thank you in advance!
There is a dedicated function for solving this problem named os.path.expandvars.
Return the argument with environment variables expanded. Substrings of the form
$nameor${name}are replaced by the value of environment variable name. Malformed variable names and references to non-existing variables are left unchanged.On Windows,
%name%expansions are supported in addition to$nameand${name}.
if not os.path.isfile(os.path.expandvars('%systemdrive%\\Work\\test\\sample.txt')):
pass # do something
You can use os.environ
import os
import os.path
fn = r'{0}\Work\test\sample.txt'.format( os.environ['systemdrive'] )
if not os.path.isfile(fn):
...
