If string is within another string

Question

Ok, so I am trying to detect whether a certain string is within another string, I have already tried using explode but it didn't work for obvious reasons, just so you can possibly get a better idea of what I am trying to accomplish, take a look at my failed attempt at using explode to try and solve my question

$stringExample1 = "hi, this is a example";

$stringExample2 = "hello again, hi, this is a example, hello again";

$expString = explode($stringExample1, $stringExample2);

if(isset($expString[1]))
{
    //$stringExample1 is within $stringExample2 !!
}
else
{
    //$stringExample1 is not within $stringExample2 :(
}

Any help will be appreciated thanks

Possible duplicate of Check if string contains specific words? — Thamilhan
– Thamilhan, Commented Aug 30, 2016 at 5:13

Samundra · Accepted Answer · 2016-08-30 06:52:15Z

2

Here strpos and strstr fails since you have extra comma in example2 in second string. We can do the string match with regular expression. See the below code snippet for example.

<?php
$str1 = "hi, this is a example";
$str2 = "hello again, hi, this is a example, hello again";
$pattern = "/$str1/";

preg_match_all($pattern, $str2, $matches);

print_r($matches);

output will be

Array
(
    [0] => Array
        (
            [0] => hi, this is a example
        )

)

If count of output array ($matches) is greater than 0 then we have the match otherwise we don't have the match. You might need to tweak the regular expression created in $pattern to suit your need and may also need optimization.

Let us know if this works for you or not.

answered Aug 30, 2016 at 6:52

Samundra

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1 Comment

JeffCoderr Over a year ago

Thanks for the answer :)

rokas · Accepted Answer · 2016-08-30 05:12:09Z

1

Try strpos

<?php
$mystring = 'abc';
$findme   = 'a';
$pos = strpos($mystring, $findme);

// Note our use of ===.  Simply == would not work as expected
// because the position of 'a' was the 0th (first) character.
if ($pos === false) {
    echo "The string '$findme' was not found in the string '$mystring'";
} else {
    echo "The string '$findme' was found in the string '$mystring'";
    echo " and exists at position $pos";
}
?>

answered Aug 30, 2016 at 5:12

rokas

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2 Comments

JeffCoderr Over a year ago

In my case $findme will include words separated by spaces... Will the use of strpos still work?

Samundra Over a year ago

@JeffCoderr see my answer and let us know if that is what you are looking for or not. I have tested the both strpos and strstr they didn't work in your case.

Dev. Joel · Accepted Answer · 2016-08-30 05:35:01Z

1

You can use strpos

if (strpos($stringExample2 , $stringExample1 ) !== false) {
  echo 'true';
}

or

strstr

if (strlen(strstr($stringExample2,$stringExample1))>0) {
    echo 'true';
}
else
{
    echo 'false';
}

edited Aug 30, 2016 at 5:35

answered Aug 30, 2016 at 5:12

Dev. Joel

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