PHP how to check the checkbox by using if else condition within echo?

Question

echo '<input type="checkbox" name="check_list[]" value="OMG" checked>';

this way will display a normal checkbox with checked. My question is that is it possible to put a if else inside the checkbox?

For example,

echo '<input type="checkbox" name="check_list[]" value="OMG" "if(2>1){ echo "checked";};" >';

The reason i want to do this is because I have a array with 6 data, if certain condition meet, the checkbox will be checked. If the echo method i mentioned above is invalid, so what's the correct way of doing that?

$zzz[1]="western food";
$zzz[2]="chinese food";
$zzz[3]="mix food";
$zzz[4]="japanese food";
$zzz[5]="korean food";
$zzz[6]="italian food";

Daniel · Accepted Answer · 2016-09-03 07:16:32Z

2

You can do this easily by concatenating your string with a ternary operator:

echo '<input type="checkbox" name="check_list[]" value="OMG" ' . ((2>1) ? "checked" : ""). '>';

The ternary operator works this way:

(2>1) ? 'checked' : ''

2>1 is considered a boolean expression (that returns either true or false). 'checked' is the result in case the boolean expression is true, and an empty string '' if it is false.

edited Sep 3, 2016 at 7:16

answered Sep 3, 2016 at 7:06

Daniel

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2 Comments

gosulove Over a year ago

the output is "checked" . any example that is the checkbox being checked after the if condition meet?

Daniel Over a year ago

@gosulove Check it out now :)

Sasikumar · Accepted Answer · 2016-09-03 07:10:51Z

1

Corrected version of your code

echo '<input type="checkbox" name="check_list[]" value="OMG" '.(2>1)?"checked":"".' >';

answered Sep 3, 2016 at 7:10

Sasikumar

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