Find String from string in java

I think the question that you want to ask here is:

How to check if an array consisting of String values separated by a comma(,) consists of all the values of another array that are also separated by a comma(,).

If that's the case, then you can't use contains() method because that serves a different purpose.

Just define your own method (for example: containsValues() here). And define the suitable logic:

import java.util.*;

public class HelloWorld {
    public static void main(String[] args) {
        String str1 = "1,3,5,7,9,11,12,14";
        String str2 = "12,3,14,";
        if (containsValues(str1, str2)) {
            System.out.println("Found!");
        }
    }

    public static boolean containsValues(String str1, String str2) {
        String strArr1[] = str1.split(",");
        String strArr2[] = str2.split(",");
        return Arrays.asList(strArr1).containsAll(Arrays.asList(strArr2));
    }
}

Output

Found!

Don't see any problem in your code. You are not getting Found!, because str1 actually does not contain "12,3,14,".

    String str1 = "1,3,5,7,9,11,12,14";
    String str2 = "12,3,14,";
    String str3 = "1,3,5";

    if (str1.contains(str2)) { //false
        System.out.println("Found!");
    }

    if (str1.contains(str3)) { //true
        System.out.println("Found!");
    }

But if you want to find them individually in str1, you may split your str2 and find them one by one.

    String str1 = "1,3,5,7,9,11,12,14";
    String str2 = "12,3,14,";       
    String s[] = str2.split(",");

    for (String str : s) {
        if(str != "" && str1.contains(str))
            System.out.println(str+ " found!");
    }

Try something like this:

String stack = "1,3,5,7,9,11,12,14";
String needle = "12,3,14,";

return Arrays.asList(stack.split(","))
       .containsAll(Arrays.asList(needle.split(",", 0)));

Notice usage of 0 in String#split() to discard empty trailing substring in malformed needle.

explore String java docs . There is split() method to do this

1. split the second string with delimiter as comma
2. Then check if every element is contained in source or not