copy some index of one array to another array

Question

I have this array,

SnegatvSph  = [NSArray arrayWithObjects:@"-0.25",@"-0.50",@"-0.75",@"-1.00",@"-1.25",@"-1.50",@"-1.75",@"-2.00",@"-2.25",@"-2.50",@"-2.75",@"-3.00",@"-3.25",@"-3.50",@"-3.75",@"-4.00",@"-4.25",@"-4.50",@"-4.75",@"-5.00",@"-5.25",@"-5.50",@"-5.75",@"-6.00",@"-6.25",@"-6.50",@"-6.75",@"-7.00",@"-7.25",@"-7.50",@"-7.75",@"-8.00",@"-8.25",@"-8.50",@"-8.75",@"-9.00",@"-9.25",@"-9.50",@"-9.75",@"-10.00",@"-10.25",@"-10.50",@"-10.75",@"-11.00",@"-11.25",     @"-11.50",@"-11.75",@"-12.00", nil];

from this array i want to add values from -4.25 to -8.50 to another array like

SpositvSph  = [NSArray arrayWithObjects:@"-4.25",@"-4.50",@"-4.75",@"-5.00",@"-5.25",@"-5.50",@"-5.75",@"-6.00",@"-6.25",@"-6.50",@"-6.75",@"-7.00",@"-7.25",@"-7.50",@"-7.75",@"-8.00",@"-8.25",@"-8.50", nil];

can anyone help me out?

NSMutableArray *arr = [NSMutableArray arrayWithArray:SpositvSph]; [arr insertObject:@"someValue" atIndex:YOURINDEX]; — Deepak Thakur
– Deepak Thakur, Commented Sep 9, 2016 at 6:41
NSArray is static and NSMutableArray is dynamic means NSArray is only init time add but NSMutableArray is any time add. — Bhadresh Kathiriya
– Bhadresh Kathiriya, Commented Sep 9, 2016 at 6:43

Nirav D · Accepted Answer · 2016-09-09 06:49:33Z

2

You can use subarrayWithRange: with NSArray like this.

NSInteger startIndex = [SnegatvSph indexOfObject:@"-4.25"];
NSInteger toIndex = [SnegatvSph indexOfObject:@"-8.50"];
if (startIndex < SnegatvSph.count && toIndex < SnegatvSph.count) {
    NSArray *newArray = [SnegatvSph subarrayWithRange:NSMakeRange(startIndex, (toIndex - startIndex + 1))];
    NSLog(@"%@",newArray);
}

answered Sep 9, 2016 at 6:49

Nirav D

72.6k12 gold badges168 silver badges187 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

copy some index of one array to another array

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related