PHP - Function inside of a variable

Question

Im currently learning my way around OOP, i have come across something in a project that im researching and im not sure what it does.

I was wondering if anyone could explain it to me in a bit of detail.

There are 2 bits, as follows

    $check_up = function($record) {
        return ($record->status == 1);
    };

Im completely lost by this as there is no $record variable set in the entire class, so where is it getting 'status' from ...

and the second example is:

    $check_up = function($record) use($website) {
        return ($record->check < $website->warning);
    };

Any help would be really appreciated to understand this.

If you say that there is no $record variable defined anywhere in the class, then it's a pretty meaningless anonymous function; but without seeing the rest of the class, we don't know — Mark Baker
– Mark Baker, Commented Sep 12, 2016 at 8:23
See for example stackoverflow.com/questions/1065188/…. Note that the $record variable is only defined in the local scope of the function. That function could be called in the scope of the $check_up variable using something like $check_up($object_that_has_a_status_property);. — jeroen
– jeroen, Commented Sep 12, 2016 at 8:24
Thats interesting, quite confusing, but still interesting ... Thanks for putting a name to it for me — BigJobbies
– BigJobbies, Commented Sep 12, 2016 at 8:32

Passionate Coder · Accepted Answer · 2016-09-12 08:24:41Z

2

As Commented try to read this anonymous function

Anonymous functions, also known as closures, allow the creation of functions which have no specified name. They are most useful as the value of callback parameters, but they have many other uses.

http://php.net/manual/en/functions.anonymous.php

answered Sep 12, 2016 at 8:24

Passionate Coder

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1 Comment

BigJobbies Over a year ago

Much appreciated :)

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