Django Capturing multiple url parameters in request.GET

Question

i am trying to get all query parameters out of an request

url/?animal__in=dog,cat&countries__in=france

I tried

animals = request.GET.get('animal__in','')
countries = request.GET.get('countries__in','')

but then animals and countries are not lists, they are just strings. Is there a more django way to do this whole capturing?

Edit: Its important that i am using it in django-admin for filtering, where these two are not the same:

url/?animal__in=dog,cat&countries__in=france
url/?animal__in=dog&animal__in=cat&countries__in=france

sebb · Accepted Answer · 2016-09-14 14:01:24Z

2

request.GET.getlist('some_list_field')

answered Sep 14, 2016 at 14:01

sebb

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Comments

Daniel Roseman · Accepted Answer · 2016-09-14 14:01:12Z

1

Send the parameters in the proper HTTP format:

?animal__in=dog&animal__in=cat&countries__in=france

and do

request.GET.getlist('animal__in')

answered Sep 14, 2016 at 14:01

Daniel Roseman

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I want to use it as a filter in django-admin: So when i try this, it is the same like: ?animal__in=cat&countries__in=france

ChrisRob · Accepted Answer · 2016-09-14 14:55:30Z

1

split(',') works fine, not really django though

animals = request.GET.get('animal__in','').split(',')
countries = request.GET.get('countries__in','').split(',')

answered Sep 14, 2016 at 14:55

ChrisRob

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