java array outofboundexception

Question

public static int[] squeeze(int[] ints) {
    int i;
    int[] temp;
    temp = new int[100];

    for (i = 0; i < ints.length; i++) {
      if (ints[i] != ints[i + 1]) {
        temp[i] = ints[i];
        }
        else{
            while (ints[i] != ints[i + 1]) {
              i++;
            }
            temp[i] = ints[i];
        }
    }

    return temp;
}

When I run this code, it gives me arrayOutOfBoundException. Can any body point the error? I am basically checking that no two consecutive numbers in an array are the same and then printing the same array but with a copy of the next number if two consecutive are same.

for loop i< ints.length-1. Since you are checking ith with ith+1 — Deendayal Garg
– Deendayal Garg, Commented Sep 15, 2016 at 19:17
now its giving me an array dump something but the outofboundException is gone. — NewProgrammer7
– NewProgrammer7, Commented Sep 15, 2016 at 19:19
In your if statement, when running through the last instance of the while loop you check to see if it's grater than i+1, and there is nothing in the position of i+1 in the array, causing the exception. Test to make sure you're not at the end of the array, before checking if the next is equal to the previous. — parabolah
– parabolah, Commented Sep 16, 2016 at 1:58

Code Whisperer · Accepted Answer · 2016-09-15 19:20:39Z

1

When

i == ints.length-1

the check

ints[i] != ints[i + 1]

will give an error since

ints[i + 1]

does not exist.

array.length gives the number of elements in the array, while the index of the array starts at 0, not at 1. So the element of an array array[array.length] will never exist and will always give an exception.

answered Sep 15, 2016 at 19:20

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