assign value from array to string

Question

i have an array of 5 objects.

i want to assign object which is at index 1, to an NSSTRING.

nsstring *abc = [array objectAtindex:1];

i know this is wrong syntax, this is returning object , something like this.

how can i get value which is at index 1 and assign it to an string?

regards

What is the concrete question? Your code is ok and gets the 2nd item of the array. — Eiko
– Eiko, Commented Oct 17, 2010 at 14:16
@ Eiko ....is it?? but its giving <gfghf:767>, object not the value . — Shishir.bobby
– Shishir.bobby, Commented Oct 17, 2010 at 14:21
See the answers - the code is the same. Maybe it's a problem with the data itself, or the way you use it. — Eiko
– Eiko, Commented Oct 17, 2010 at 14:23
pheww..m going crazy on this..i hv an array with 5 objects..and when i am assinging it through these snippets its showing me <hghj:878>...crazzzzzy. — Shishir.bobby
– Shishir.bobby, Commented Oct 17, 2010 at 14:37

Jack · Accepted Answer · 2010-10-17 14:15:54Z

7

Erm.. this is the correct syntax :)

Apart the name of the string class:

NSString *abc = [array objectAtIndex:1];

mind that this won't create a copy of the string, if you need to copy it use

NSString *abc = [NSString stringWithString:[array objectAtIndex:1]];

As Eiko notes you can directly copy the string object if you need to:

NSString  *abc = [[array objectAtIndex:1] copy];

answered Oct 17, 2010 at 14:15

Jack

134k33 gold badges252 silver badges349 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

Eiko Over a year ago

Why not just [[array objectAtIndex:1] copy] ?

Jack Over a year ago

That's true, because I thought it would confuse him, let me add it

Jack Over a year ago

Copied your answer? what are you talking about? you also answered 2 minutes later than me. This is called whine and man, please, avoid being childish.

Shishir.bobby Over a year ago

hi ,thanks for response...i quick question...my array on console showing this "<Coffee: 0x722f460>" but when i tried ur snippet, i am getting crash log saying..."[NSMutableArray objectAtIndex:]: index 1 beyond bounds [0 .. 0]" what does dat even means? i hv objects in array, how can it be out of range??

Jack Over a year ago

because arrays are 0-based. This means that first element is at index 0, so use objectAtIndex:0 instead that 1.

Jordan · Accepted Answer · 2010-10-17 14:33:38Z

2

Arrays are zero based in Objective-C land. So...

NSArray *array = [NSArray arrayWithObjects:@"one", @"two", nil];
NSString *abc = [array objectAtIndex:1];

Would return the second object in the array. Zero would return the first.

edited Oct 17, 2010 at 14:33

answered Oct 17, 2010 at 14:13

Jordan

21.8k10 gold badges54 silver badges63 bronze badges

7 Comments

Eiko Over a year ago

Why do you create an object in line 1 and throw it away in the 2nd?

user23743 Over a year ago

@Jack: whatever other problems exist with this answer, a leak isn't one of them.

Eiko Over a year ago

Well at least it has zero length and is autoreleased. It's a bug though and can easily break your code in a tight loop.

Jordan Over a year ago

@Jack, We're not talking about a loop are we? First you copy my answer, then you vote me down, then you troll... nice.

Jack Over a year ago

@Jordan: let's assume -init instead that +string :)

|

Collectives™ on Stack Overflow

assign value from array to string

2 Answers 2

5 Comments

7 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

5 Comments

7 Comments

Your Answer

Sign up or log in

Post as a guest

Related