FireFox Javascript event handling

Question

I have the following function that works in Chrome/IE:

for(var i = 0; i < 5; ++i) {
        document.all["elems" + i].onscroll = getFunc("onScrollAdj(document.all['tb" + i + "']);");
    }

function getFunc(jsString) {
    return new Function(jsString);
}

However I get the error:

ReferenceError: event is undefined.

I have tried to re-write the function to include an event however I then get another error:

var i is undefined.

document.all["elems" + i].onscroll = onScrollAdj(event, document.all['tb" + i + "');

Is there any way to ensure both event and attributes can be passed?

what is onScrollAdj - I bet that has a reference to event - which used to be an internet explorer "kludge" that for some reason Chrome decided to implement — Jaromanda X
– Jaromanda X, Commented Sep 21, 2016 at 11:09

T.J. Crowder · Accepted Answer · 2016-09-21 11:10:20Z

2

however I get 'ReferenceError: event' is undefined.

That's because you're trying to use event without declaring it as an argument. That only works on Microsoft browsers, which make event a global, and Chrome which throws a bone to Microsoft-only code. You will need to declare the argument.

There's no need for new Function virtually ever, and certainly not in this case:

for(var i = 0; i < 5; ++i) {
    document.all["elems" + i].onscroll = getFunc(i);
    // ------------------------------------------^
}

function getFunc(i) {
// --------------^
    return function(event) { onScrollAdj(event, document.all['tb' + i]); };
    // -------------^--------------------^
}

Note that you'll have to ensure that onScrollAdj accepts event:

function onScrollAdj(event, tbThingy) {
// ------------------^

answered Sep 21, 2016 at 11:10

T.J. Crowder

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