inserting variables into php echo of a submit button

Question

Hi I'm looking to insert a varible into a submit buttons name when I echo it via a loop so that each button has a unique name

   $x=0;
            $sql = "SELECT * FROM userstats ORDER BY RAND() LIMIT 5; ";
            $result = mysqli_query($link,$sql);
            echo ("<table>");
            echo ("<tr>");
            echo ("<th>Name</th>");
            echo ("<th>Level</th>");
            echo ("<th>Stats</th>");
            echo ("<th>Win Chance</th>");
            echo ("<th>Action</th>");
            echo ("</tr>");
            while($row = mysqli_fetch_assoc($result)){
                if($row['username'] !== $_SESSION['username']){//add so it dosent put duplicates
                    echo("<tr>");
                    echo("<th>".$row['username']." </th>");
                    echo("<th>Level: ".$row['Level']." </th>");
                    echo("<th>Player Stats:".$row['Attack']."/".$row['Defence']." </th>");
                    echo("<th>Win Chance: ");
                    echo(CalculateWinChance($link,$row['Defence']));
                    echo("<input type='hidden' name='".$x."hidden1' value='".$row['Defence']."' />");
                    echo("<input type='hidden' name='".$x."hidden2' value='".$row['username']."' />");
                    echo("<th><input type='submit' name = 'Attack_Btn".$x."' onclick = 'BattlePlayers()' value ='Attack'></th>");
                    echo("</tr>");
                    $x=$x+1;
                }
            }
            echo ("</table>");

I tried the above code but it does not change the name attribute? What am I doing wrong here?

Maybe $x is empty and please use better names for your variables. — Phiter
– Phiter, Commented Sep 21, 2016 at 16:00
what does the CalculateWinChance() function do, or do you feel it's not relevant to the question/problem? and did you start the session? Check for errors via PHP and MySQL, run a var_dump and look at your HTML source. — Funk Forty Niner
– Funk Forty Niner, Commented Sep 21, 2016 at 16:02
"$ is not empty its prining as expected 01234" - The leading zero is treated as an octal, that's why it's failing. — Funk Forty Niner
– Funk Forty Niner, Commented Sep 21, 2016 at 16:10

Community · Accepted Answer · 2020-06-20 09:12:55Z

3

you can put that as an answer can ill accept it :) – GregHBushnell

Posting from comments:

"$ is not empty its prining as expected 01234" - The leading zero is treated as an octal, that's why it's failing. . – Fred -ii

thank you very much that solved it :) what is an octal ? – GregHBushnell

References:

Footnote:

echo is a language construct and not a "function" per se. So, you can safely omit all of the (), since that's just more code than needed really.

Reference:

http://php.net/manual/en/function.echo.php

edited Jun 20, 2020 at 9:12

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answered Sep 21, 2016 at 16:14

Funk Forty Niner

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