I am trying to pass a String to my BufferedReader. How can I pass "test" as String to the reader rather than the input from System.in ?
String test = "test";
BufferedReader inFromUser = new BufferedReader(new InputStreamReader(System.in));
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2 Answers
You can modify your code as below
String test = "test";
Reader inputString = new StringReader(test);
BufferedReader reader = new BufferedReader(inputString);
Comments
No point in buffering a string. Just
String aString = ...;
Reader inFromUser = new StringReader(aString);
7 Comments
water
but how to send it to the server in this way. Can u please adapter your answer to my code to understand your solution?
water
String message = "#2016011400#"; Socket clientSocket = new Socket("localhost", 39537); DataOutputStream outToServer = new DataOutputStream(clientSocket.getOutputStream()); outToServer.writeBytes(message + '\n'); clientSocket.close();. I have tried the following but it does not work for me.
Jonathan E. Landrum
there is a point in buffering a String if it's huge and you want to read it line-by-line
Alexey Romanov
@JonathanLandrum If you have a String, it's already fully in memory by definition. If you just mean that
BufferedReader has the lines() method, and StringReader doesn't, fair enough, but it's fixed in Java 11 (docs.oracle.com/en/java/javase/11/docs/api/java.base/java/lang/…).
Balázs Németh
A point might be: unit testing a method which expects a
BufferedReader, and providing it as a String is the easiest. |