How do I limit my users input to a single digit? (Python)

Question

I want my program to say 'invalid input' if 2 digits or more are entered so is there a way i can limit my users input to a single digit in python?

This is my code:

print('List Maker')
tryagain = ""

while 'no' not in tryagain:
    list = []

    for x in range(0,10):
        number = int(input("Enter a number: "))
        list.append(number)

    print('The sum of the list is ',sum(list))
    print('The product of the list is ',sum(list) / float(len(list)))
    print('The minimum value of the list is ',min(list))
    print('The maximum vlaue of the list is ',max(list))
    print(' ')
    tryagain = input('Would you like to restart? ').lower()
    if 'no' in tryagain:
        break
print('Goodbye')

if number >9 or number <-9

Daniel Lee
– Daniel Lee

2016-09-26 13:47:30 +00:00
Commented Sep 26, 2016 at 13:47 — Daniel Lee
– Daniel Lee, Commented Sep 26, 2016 at 13:47
alternatively, while number <=9 and number >=-9

Daniel Lee
– Daniel Lee

2016-09-26 13:48:30 +00:00
Commented Sep 26, 2016 at 13:48 — Daniel Lee
– Daniel Lee, Commented Sep 26, 2016 at 13:48

Martijn Pieters · Accepted Answer · 2016-09-26 13:48:32Z

4

Use a while loop instead of a for loop, break out when you have 10 digits, and refuse to accept any number over 9:

numbers = []
while len(numbers) < 10:
    number = int(input("Enter a number: "))
    if not 1 <= number <= 9:
        print('Only numbers between 1 and 9 are accepted, try again')
    else:
        numbers.append(number)

Note that I renamed the list used to numbers; list is a built-in type and you generally want to avoid using built-in names.

answered Sep 26, 2016 at 13:48

Martijn Pieters

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4 Comments

Aaron Over a year ago

Is input() safe in python 2? from what I've read it is similar to eval(raw_input())

Steven Rumbalski Over a year ago

@Aaron: OP appears to be using Python 3. If OP is using Python 2 then OP should use raw_input instead of input for the reason you stated.

Aaron Over a year ago

@StevenRumbalski I see that, and I understand that input() functions as raw_input() in Python 3. But I was curious if the 2.7 version was safe from an untrusted input point of view. (not in relation to this question...)

Martijn Pieters Over a year ago

@Aaron: in Python 2, input() is not safe, no, as it is an automatic eval(raw_input()). This isn't Python 2 however.

Community · Accepted Answer · 2017-05-23 12:25:36Z

0

There is another option for getting only one character, based on this previous answer:

import termios
    import sys, tty
    def getch():
        fd = sys.stdin.fileno()
        old_settings = termios.tcgetattr(fd)
        try:
            tty.setraw(fd)
            ch = sys.stdin.read(1)
        finally:
            termios.tcsetattr(fd, termios.TCSADRAIN, old_settings)
        return ch


numbers = []
while len(numbers) < 10:
    try:
        ch = int(getch())
    except:
        print 'error...'

edited May 23, 2017 at 12:25

CommunityBot

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answered Sep 26, 2016 at 14:08

Gal Dreiman

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