PHP How assign value to some default function arguments

Question

In following function we have some arguments with default value, How can I call that function with assigning value to some of them.

function foo($a, $b='def b', $c='def c', $d='def d'){
   //....
}
//call foo for $a='nu a' and $c='nu c'
foo('nu a', $c='nu c'); //but b will be assigned

I want to set value for $c and don't want to assign all of them just for $c.

Not acceptable solution:

foo('nu a', 'def b', 'nu c');
Not acceptable solution

//moving c to second argument function foo($a, $c='def c', $b='def b', $d='def d'){ }

So argument is after some default arguments and I don't want to set default value for previous arguments just for one

is it possible to move all the possible defaults to the right of the function arguments ? — atoms
– atoms, Commented Sep 29, 2016 at 14:20

M.Alnashmi · Accepted Answer · 2016-09-29 14:45:22Z

0

Not possible. You're looking for named parameters which is not supported by php.

If you want to do this, you'll have to change your parameter to a single array, and in the function body extract what you need based on the keys.

Other than that, you cannot pass on a value of variable c without passing in b.

answered Sep 29, 2016 at 14:45

M.Alnashmi

5921 gold badge5 silver badges15 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Anass · Accepted Answer · 2016-09-29 19:09:59Z

There's no way to "skip" an argument other than to specify a default like false, '' or null.

You will use something like this:

function foo($settings) {
   $a = $settings['a'];
   $b = $settings['b'];
   $c = $settings['c'];
   $d = $settings['d'];
   # code...
}

foo($settings = array(
    'a' => null,
    'b' => 'def b',
    'c' => 'def c',
    'd' => 'def d',
));

Or, in an indexed array, you're able to use list() construct to handle array values, like this :

function foo($settings) {
   list($a, $b, $c, $d) = $settings;
   # code...
}

foo(array(null, 'def b', 'def c', 'def d'));

At the very least you can move whatever you think is not expected most of the time to the end of the argument list in the function definition.

function foo($a, $b = 'def b', $c = 'def c', $d = 'def b') {
   # code...
}
foo($a = 'def a');

Collectives™ on Stack Overflow

PHP How assign value to some default function arguments

2 Answers 2

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related