Golang HTTP XML Parsing issue

Question

I'm trying to access an XML file available online, but after the GET the XML format disappears.
What am I doing wrong?
Thank you so much!

func getHttp(address string) string{
    resp, err := http.Get(address)
    resp.Header.Add("Content-Type","application/xml; charset=utf-8")
    if err != nil {
        panic(err)
    }

    defer resp.Body.Close()

    data, err := ioutil.ReadAll(resp.Body)
    if err != nil {
        panic(err)
    }

    return (string(data))
}

The new format looks like this:

{"SessionKey":"229eaeaa9fb14a0d85ff38ae4e0c7870_ecilpojl_018FC93424D13ECC0908CE5BC5E3F86B","Query":{"Country":"GB","Currency":"GBP","Locale":"en-gb","Adults":1,"Children":0,"Infants":0,"OutboundDate":"2016-10-08","LocationSchema":"Default","CabinClass":"Economy","GroupPricing":false},

instead of

<SessionKey>229eaeaa9fb14a0d85ff38ae4e0c7870_ecilpojl_018FC93424D13ECC0908CE5BC5E3F86B</SessionKey>
  <Query>
    <Country>GB</Country>
    <Currency>GBP</Currency>
    <Locale>en-gb</Locale>
    <Adults>1</Adults>
    <Children>0</Children>
    <Infants>0</Infants>
    <OutboundDate>2016-10-08</OutboundDate>
    <LocationSchema>Default</LocationSchema>
    <CabinClass>Economy</CabinClass>
    <GroupPricing>false</GroupPricing>
  </Query>

The problem is in your main. Show your main function: stackoverflow.com/help/mcve and you don't need: resp.Header.Add("Content-Type","application/xml; charset=utf-8") — user6169399
– user6169399, Commented Oct 2, 2016 at 10:54
If I click on the link the browser generates an xml file, but after the GET it changes — jgulacsy
– jgulacsy, Commented Oct 2, 2016 at 11:07
The server is sending json based on the request, maybe the user agent in this case. Why not use the json? It will be easier to unmarshal and contain the same data. — Mr_Pink
– Mr_Pink, Commented Oct 2, 2016 at 11:23

score 1 · Accepted Answer · 2016-10-02 11:29:11Z

1

See: https://www.whatismybrowser.com/detect/what-http-headers-is-my-browser-sending

Try this (and replace the web address with yours):

package main

import (
    "fmt"
    "io/ioutil"
    "net/http"
)

func main() {
    fmt.Println(getHttp(`http://stackoverflow.com/`))
}
func getHttp(url string) string {    
    client := &http.Client{}
    req, err := http.NewRequest("GET", url, nil)
    if err != nil {
        panic(err)
    }
    req.Header.Set("ACCEPT", "application/xhtml+xml,application/xml")
    resp, err := client.Do(req)
    if err != nil {
        panic(err)
    }
    defer resp.Body.Close()
    data, err := ioutil.ReadAll(resp.Body)
    if err != nil {
        panic(err)
    }
    return string(data)
}

I hope this helps.

edited Oct 2, 2016 at 11:29

answered Oct 2, 2016 at 11:15

user6169399

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2 Comments

Mr_Pink Over a year ago

Content-Type is for the data in the request but you're not sending any. The Accept header is the standard way to request a data type.

Mr_Pink Over a year ago

You don't specify the encoding. Just ("Accept", "application/xml")

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