Parsing a list into a url string

Question

I have a list of tags that I would like to add to a url string, separated by commas ('%2C'). How can I do this ? I was trying :

>>> tags_list
['tag1', ' tag2']
>>> parse_string = "http://www.google.pl/search?q=%s&restofurl" % (lambda x: "%s," %x for x in tags_list)

but received a generator :

>>> parse_string
'http://<generator object <genexpr> at 0x02751F58>'

Also do I need to change commas to %2C? I need it to feedpaarser to parse results. If yes - how can I insert those tags separated by this special sign ?

EDIT:

parse_string = ""
for x in tags_list:
    parse_string += "%s," % x

but can I escape this %2C ? Also I'm pretty sure there is a shorter 'lambda' way :)

mechanical_meat · Accepted Answer · 2010-10-21 05:06:53Z

4

parse_string = ("http://www.google.pl/search?q=%s&restofurl" % 
               '%2C'.join(tag.strip() for tag in tags_list))

Results in:

>>> parse_string = ("http://www.google.pl/search?q=%s&restofurl" %
...                '%2C'.join(tag.strip() for tag in tags_list))
>>> parse_string
'http://www.google.pl/search?q=tag1%2Ctag2&restofurl'

Side note:
Going forward I think you want to use format() for string interpolation, e.g.:

>>> parse_string = "http://www.google.pl/search?q={0}&restofurl".format(
...                '%2C'.join(tag.strip() for tag in tags_list))
>>> parse_string
'http://www.google.pl/search?q=tag1%2Ctag2&restofurl'

answered Oct 21, 2010 at 5:06

mechanical_meat

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2 Comments

sasklacz Over a year ago

I love those python one-liners :)

mechanical_meat Over a year ago

sometimes they're the only things getting me through the day

Tobias · Accepted Answer · 2010-10-21 08:13:27Z

1

"%s" is fine, but urlparse.urlunparse after urllib.urlencode is safer.

str.join is fine, but remember to check your tags for commas and number signs, or use urllib.quote on each one.

answered Oct 21, 2010 at 8:13

Tobias

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1 Comment

sasklacz Over a year ago

so what would be the final solution ?

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