Ruby Array: string into integer

Question

I'm new to Ruby. I have a series of arrays with two strings each:

["[[\"Wayfair \", \"57\"]]", "[[\"Move24 \", \"26\"]]",
  "[[\"GetYourGuide \", \"25\"]]", "[[\"Visual Meta \", \"22\"]]",
  "[[\"FinLeap \", \"20\"]]", "[[\"Movinga \", \"20\"]]",
  "[[\"DCMN \", \"19\"]]", ...

I am trying to convert the string with the number of each array into an integer, but I get something else than I expect:

companies = companies.map do |company|
  c = company[0].scan(/(.+)\((\d+)\)/).inspect
  [c[0], c[1].to_i]
end

puts:

["[", 0], ["[", 0], ["[", 0], ["[", 0], ["[", 0], ["[", 0],
  ["[", 0], ["[", 0], ["[", 0], ["[", 0], ["[", 0]]

I am expecting:

 ["Wayfair", 57],  ["Move24", 26], ["GetYourGuide", 25], ...

please help?

Full code :

require 'net/http'
require 'uri'

uri = URI('http://berlinstartupjobs.com/') #URI takes just one url
req = Net::HTTP::Get.new(uri) #get in URI
req['User-Agent'] = 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36   (KHTML, like Gecko) Chrome/53.0.2785.116 Safari/537.36' #use this header


res = Net::HTTP.start(uri.hostname, uri.port) {|http| http.request(req)} # URI documentation

puts res.code #status code

puts res.body

puts res.body.scan('<a href="http://berlinstartupjobs.com/companies/') #scan in the body of the document files that match a href=...

puts res.body.scan(/<a href="http:\/\/berlinstartupjobs\.com\/companies\/[^\s]+ class="tag-link">(.*)<\/a>/) #scan

companies = res.body.scan(/<a href="http:\/\/berlinstartupjobs\.com\/companies\/[^\s]+ class="tag-link">(.*)<\/a>/)


companies = companies.map do |company|
  c = company[0].scan(/(.+)\((\d+)\)/).inspect
  [c[0], c[1].to_i]
end # do ... end = { }

  puts companies.inspect

Can you show the expected output too?

Tamas Rev
– Tamas Rev

2016-10-04 07:57:02 +00:00
Commented Oct 4, 2016 at 7:57 — Tamas Rev
– Tamas Rev, Commented Oct 4, 2016 at 7:57
The way I see it, you have a flat array of strings.

Sergio Tulentsev
– Sergio Tulentsev

2016-10-04 07:57:39 +00:00
Commented Oct 4, 2016 at 7:57 — Sergio Tulentsev
– Sergio Tulentsev, Commented Oct 4, 2016 at 7:57
Yeh, would be nice to see expected output

Yaro
– Yaro

2016-10-04 07:58:54 +00:00
Commented Oct 4, 2016 at 7:58 — Yaro
– Yaro, Commented Oct 4, 2016 at 7:58
Please, provide a minimal reproducible example.

Sergio Tulentsev
– Sergio Tulentsev

2016-10-04 07:59:25 +00:00
Commented Oct 4, 2016 at 7:59 — Sergio Tulentsev
– Sergio Tulentsev, Commented Oct 4, 2016 at 7:59
I've updated the question with full info.

catch22
– catch22

2016-10-04 08:04:26 +00:00
Commented Oct 4, 2016 at 8:04 — catch22
– catch22, Commented Oct 4, 2016 at 8:04

Sergio Tulentsev · Accepted Answer · 2016-10-04 08:25:54Z

1

Your code was mostly ok. Just drop that .inspect at the end. It returns a string, not array.

# this is what you get from the scraping.
companies = [["Wayfair (57)"], ["Move24 (26)"], ["GetYourGuide (25)"]]

companies = companies.flatten.map do |company|
  c = company.scan(/(.+)\((\d+)\)/).flatten
  [c[0], c[1].to_i]
end

p companies
# >> [["Wayfair ", 57], ["Move24 ", 26], ["GetYourGuide ", 25], ...]

edited Oct 4, 2016 at 8:25

answered Oct 4, 2016 at 8:17

Sergio Tulentsev

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1 Comment

catch22 Over a year ago

hey Sergio thank you so much - this is what I needed. I had a feeling flatten was the quid and been playing with it, but not this way. Thanks again :)

Hck · Accepted Answer · 2016-10-04 08:08:52Z

1

You can achieve this by using Enumerable#map & parsing each element using JSON.parse:

require 'json'

companies.map { |elem| key, val = JSON.parse(elem).flatten; [k.strip, v.to_i] }

Instead of JSON.parse you also can use eval, but using eval is considered to be a bad practice.

answered Oct 4, 2016 at 8:08

Hck

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1 Comment

Sergio Tulentsev Over a year ago

nah, his data is not like this. OP just messed up the printing.

dku.rajkumar · Accepted Answer · 2016-10-04 08:11:41Z

1

arr = ["[[\"Wayfair \", \"57\"]]", "[[\"Move24 \", \"26\"]]"]
result = arr.collect{|e| JSON.parse(e)[0].map{|name, value| [name.strip, value.to_i]}}

OUTPUT:
[[Wayfair, 57], [Move24", 26]]

answered Oct 4, 2016 at 8:11

dku.rajkumar

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1 Comment

Sergio Tulentsev Over a year ago

nah, his data is not like this. OP just messed up the printing.

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