Issue with pattern program using loops

Question

I'm writing a program that takes two inputs, number of lines and number of cheers as input. The number of lines is how many lines the user wants to print out and the number of cheers are in the format that 1 cheer is the word "GO" and two cheers are two "GO" s ...and their is the word "BUDDY" within two neighboring GO's. And each new line has to be indented 3 spaces more then the one before. And this is the program I've come up with:

lines = input("Lines= ")
cheers = input("Cheers= ")
if cheers == 1:
    i = 1
    space = 0
    S = ""
    while i<=lines:
        S=S+(" "*space)+"GO \n"
        i += 1
        space+=3
    print S
else:
    n = 1
    cheer1 = "GO BUDDY "
    cheer2 = "GO"
    space = 0
    while n<= cheers:
        print (" "*space)+(cheer1*cheers)+cheer2
        space+=3
        n += 1

But the problem with this is that it doesn't print out the right number of GO's in the number of cheers. How can I modify my code to fix this problem? This is the output format I want to get :

jackdaw · Accepted Answer · 2016-10-08 11:48:58Z

1

Often in Python you don't need any loops

lines = int(input('Lines= '))
cheers = int(input('Cheers= '))

line = ' BUDDY '.join(['GO']*cheers)
for i in range(cheers):
     print(' '*(i*3) + line)

answered Oct 8, 2016 at 11:48

jackdaw

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1 Comment

Hammad Manzoor Over a year ago

Yes you are right, actually I was asked specifically to write the code using loops.

WayToDoor · Accepted Answer · 2016-10-08 11:50:59Z

1

def greet(lines, cheers):
    i = 0
    line_str = ""
    while i < cheers: # Build the line string
        i += 1
        line_str += "GO" if i == cheers else "GO BUDDY "

    i = 0 
    while i < lines: #Print each line
        print(" "*(i*3) + line_str)
        i += 1

greet(2,1)
greet(4,3)
greet(2,4)

edited Oct 8, 2016 at 11:50

answered Oct 8, 2016 at 11:36

WayToDoor

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2 Comments

Hammad Manzoor Over a year ago

That's exactly the same output as my program. I need as many "GO" words in one line as the number given to 'cheers' ... e.g; for lines = 3 and cheers = 3 output should be "GO BUDDY GO BUDDY GO" ..which has 3 "GO" words.

WayToDoor Over a year ago

You can try it now @HogRider123

Harv · Accepted Answer · 2016-10-08 12:19:45Z

1

Try this.

def greet(lines, cheers):
    for i in range (lines):
        output = (" ") * i + "Go"

        for j in range (cheers):
            if cheers == 1:
                print output
                break
            output += "Budddy Go"
        print output

Hope this helps.

edited Oct 8, 2016 at 12:19

answered Oct 8, 2016 at 11:57

Harv

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1 Comment

Harv Over a year ago

put if cheer == 1 block inside cheers loop. I'll update the code

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