Using for loop to create JSON object in PHP

Question

I am trying to create a JSON object like this:

"results": [
{"key":"1","trackname":"[email protected]"},
{"key":"1","trackname":"[email protected]"},
]

However my PHP code is creating a new object for each iteration, the json looks like this:

0: "{"key":"1","trackname":"[email protected]"}"
1: "{"key":"1","trackname":"[email protected]"}"

Here is my php:

$results = array();

function json_response($trackName) {
return json_encode(array(
    'key' => '1',
    'trackname' => $trackName
));
}

//There is 3 reg expressions for each primary array so we need to iterate by 3, otherwise we will get 3 lots of the same email address
for ($i = 0; $i < $numMatches; $i = $i + $patternNum) {
    $results[] = json_response($matches[0][$i]);
}
//$results = call_user_func_array('array_merge',$results);
echo json_encode($results);

what is your problem?

ashkufaraz
– ashkufaraz

2016-10-10 07:46:20 +00:00
Commented Oct 10, 2016 at 7:46 — ashkufaraz
– ashkufaraz, Commented Oct 10, 2016 at 7:46

Richard · Accepted Answer · 2016-10-10 09:21:05Z

2

you need to remove the first json_encode function

you can either try to create associative array or use function compact, that will do the work for you.

//There is 3 reg expressions for each primary array so we need to iterate by   3, otherwise we will get 3 lots of the same email address
  for ($i = 0; $i < $numMatches; $i = $i + $patternNum) {
    $results[] = $matches[0][$i]; // json_encode removed
}

echo json_encode(array('results' => $results));
// or
echo json_encode(compact('results'));

answered Oct 10, 2016 at 9:21

Richard

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Comments

devneri · Accepted Answer · 2016-10-10 07:51:19Z

1

In final echo you encode in json an array already encoded.

Remove json_encode from json_response function.

answered Oct 10, 2016 at 7:51

devneri

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