How to retrieve value from object in JavaScript

Question

Hi I am using a Java script variable

var parameter = $(this).find('#[id$=hfUrl]').val();

This value return to parameter now

"{'objType':'100','objID':'226','prevVoting':'"   // THIS VALUE RETURN BY

$(this).find('[$id=hfurl]').val();

I want to store objType value in new:

 var OBJECTTYPE = //WHAT SHOULD I WRITE so OBJECTTYPE contain 400

I am trying

OBJECTTYPE = parameter.objType; // but it's not working...

What should I do?

Are you sure that parameter contains this value? First, the object is malformed (but maybe you just forgot a ') and second, it seems unlikely to me that .find('[$id=hfurl]') returns such an object (if you are using jQuery). Do you get any errors on the console? — Felix Kling
– Felix Kling, Commented Oct 22, 2010 at 10:33
"{'objType':'100','objID':'226','prevVoting':'" is still not correct syntax. What about errors? $(this).find('[$id=hfurl]') likely returns a jQuery object. Are you using jQuery? — Felix Kling
– Felix Kling, Commented Oct 22, 2010 at 10:38
THIS IS CORRECT ACTUALLY I AM STORING {'objType':'100','objID':'226','prevVoting':' IN HIDDEN FIELD VALUE AND ON CLIENT SIDE I AM RETRIVING IT THATS ALL... — Nishant Kumar
– Nishant Kumar, Commented Oct 22, 2010 at 10:40
It would help us very much, if you'd answer my questions: Are you getting errors on the console? and Are you using jQuery? — Felix Kling
– Felix Kling, Commented Oct 22, 2010 at 10:49

abahgat · Accepted Answer · 2010-10-22 10:32:24Z

1

Try using parameter['objType'].

Just a note: your code snippet doesn't look right, but I guess you just posted it wrong.

answered Oct 22, 2010 at 10:32

abahgat

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2 Comments

Felix Kling Over a year ago

Assuming everything else is correct, if parameter['objType'] works, then parameter.objType should work too.

abahgat Over a year ago

Your updated code changes things a bit :) Felix has just posted a perfect answer to you question, then

Felix Kling · Accepted Answer · 2010-10-22 10:56:37Z

1

Ok, not sure if I am correct but lets see:

You say you are storing {'objType':'100','objID':'226','prevVoting':' as string in a hidden field. The string is not a correct JSON string. It should look like this:

{"objType":100,"objID":226,"prevVoting":""}

You have to use double-quotes for strings inside a JSON object. For more information, see http://json.org/

Now, I think with $(this).find('[$id=hfurl]'); you want to retrieve that value. It looks like you are trying to find an element with ID hfurl,but $id is not a valid HTML attribute. This seems like very wrong jQuery to me. Try this instead:

var parameter = $('#hfurl').val();

parameter will contain a JSON string, so you have to parse it before you can access the values:

parameter = $.parseJSON(parameter);

Then you should be able to access the data with parameter.objType.

Update:

I would not store "broken" JSON in the field. Store the string similar to the one I shoed above and if you want to add values you can do it after parsing like so:

parameter.vote = vote;
parameter.myvote = vote;

It is less error prone.

edited Oct 22, 2010 at 10:56

answered Oct 22, 2010 at 10:46

Felix Kling

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2 Comments

Nishant Kumar Over a year ago

actually u r correct "{'objType':'100','objID':'226','prevVoting':'" what i am doing here am adding some another value to it like parameter++ vote + "','myvote':'" + vote + "'}",

Felix Kling Over a year ago

@Nishant: Ok, that does not matter, but the strings inside the object must be enclosed in double-quotes. Could you please edit your question and add the corresponding line where you are adding the other string?

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