Invalid Syntax error python 3.5.2

Question

I'm getting syntax error in this particular line.

print "Sense %i:" %(i),

Full code:

for i in range(len(meas)):
    p = sense(p, meas[i])
    r = [format(j,'.3f') for j in p]
    print "Sense %i:" % (i),
    print r,
    entropy(p)
    p = move(p, mov[i])
    r = [format(j,'.3f') for j in p]
    print "Move %i:" % (i),
    print r,
    entropy(p)
    print

Which is the version of Python you're using? If it's Python 3 your code will have to look like this: print("Sense %i:" % (i), end=""). — Matthias
– Matthias, Commented Oct 11, 2016 at 21:27
When i try making changes in the code i get error in next line — gopal joshi
– gopal joshi, Commented Oct 11, 2016 at 21:34
In that case you might be missing a closing parentheses in the line before this. — Matthias
– Matthias, Commented Oct 11, 2016 at 21:40
for i in range(len(meas)): p = sense(p, meas[i]) r = [format(j,'.3f') for j in p] print "Sense %i:"%(i), print r, entropy(p) p = move(p, mov[i]) r = [format(j,'.3f') for j in p] print "Move %i:"%(i), print r, entropy(p) print — gopal joshi
– gopal joshi, Commented Oct 11, 2016 at 21:59

Laurent LAPORTE · Accepted Answer · 2016-10-12 07:01:02Z

1

Several things:

In Python 3, print is a function, no more a statement like it was with Python 2. So, you need to add parenthesis to call the function,
the % operator used for string formatting is deprecated. With Python 3, you should use the format method (or the format function),
the % operator usually take a tuple as a second parameter: the expression "(i)" is not a tuple but a constant. With Python, the singleton tuple has a trailing comma like this: "(i,)".
use the keyword argument end="" to replace the newline by an empty string (but I'm not sure this is what you want)

So, you can replace your code by:

print("Sense {}:".format(i), end="")

EDIT: add code from comment

Your code should be converted in Python 3 like bellow:

for i in range(len(meas)):
    p = sense(p, meas[i])
    r = [format(j,'.3f') for j in p]
    print("Sense {0}:".format(i), end="")
    print(r, end="")
    entropy(p)
    p = move(p, mov[i])
    r = [format(j,'.3f') for j in p]
    print("Move {0}:".format(i), end="")
    print(r, end="")
    entropy(p)
    print()

edited Oct 12, 2016 at 7:01

answered Oct 11, 2016 at 21:31

Laurent LAPORTE

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2 Comments

gopal joshi Over a year ago

for i in range(len(meas)): p = sense(p, meas[i]) r = [format(j,'.3f') for j in p] print "Sense %i:"%(i), print r, entropy(p) p = move(p, mov[i]) r = [format(j,'.3f') for j in p] print "Move %i:"%(i), print r, entropy(p) print

gopal joshi Over a year ago

Thanks a lot !!! it works perfectly fine now... Actually i am just beginner in python programming. I would like to know if you can help me with other codes. Thanks again.

Oz Bar-Shalom · Accepted Answer · 2016-10-11 21:26:16Z

0

Try this:

print ("Sense %s:" %i)

Will work just fine

answered Oct 11, 2016 at 21:26

Oz Bar-Shalom

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Comments

yonizxz · Accepted Answer · 2016-10-11 21:26:40Z

0

In python 3, print is a function, you have to use brackets: print("Sense %i:" %(i))

answered Oct 11, 2016 at 21:26

yonizxz

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1 Comment

gopal joshi Over a year ago

print ("Sense %i:"%(i)) print r, entropy(p) p = move(p, mov[i]) r = [format(j,'.3f') for j in p] print "Move %i:"%(i), print r, entropy(p)

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