I have a simple XML, that I want to add a new root to. The current root is <myFields> and I want to add <myTable> so it would look like.
<myTable>
<myFields>
.
.
</myFields>
</myTable>
-
Good question, +1. See my answer for the most likely shortest solution. :) It is also correct!Dimitre Novatchev– Dimitre Novatchev2010-10-22 19:13:18 +00:00Commented Oct 22, 2010 at 19:13
Add a comment
|
4 Answers
Something like this should work for you...
<xsl:template match="/">
<myTable>
<xsl:apply-templates/>
</myTable>
</xsl:template>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
3 Comments
Marsharks
almost works, but there are not longer any child elements, only values
Marsharks
yes, I saw that. Mine is an InfoPath form. My solution works for me.
This is probably the shortest solution :) :
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<myTable>
<xsl:copy-of select="node()" />
</myTable>
</xsl:template>
</xsl:stylesheet>
answered Oct 22, 2010 at 19:13
Dimitre Novatchev
244k27 gold badges307 silver badges438 bronze badges
Comments
This stylesheet:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/*">
<myTable>
<xsl:call-template name="identity"/>
</myTable>
</xsl:template>
<xsl:template match="@*|node()" name="identity">
<xsl:copy>
<xsl:apply-templates/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
Note: Copy everything (also PIs before root element), and add myTable befere root element.
Comments
you helped get me close enough
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:element name="myTable">
<xsl:copy-of select="*" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
1 Comment
Mads Hansen
If you care to preserve any comments or processing-instructions that might be before the document element, then @Ryan Berger's solution is the way to go.