Error in Passing Jquery variable to a php session variable with ajax

Question

This question might seem a duplicate and There are many posts on how to pass jquery variables to php. Tried all of them none worked for me.

Here is what all I did.

From Jquery:

$.ajax({
       url: '/test.php',
       data: {"name":name,"phone":phone},
       type: 'post',
       success:function(data){
           console.log("Succses"); 
       }
    });

In test.php

session_start();
$_SESSION['name'] = $_POST['name'];
$_SESSION['phone']=$_POST['phone'];

There is nothing complex in this code. It is so simple and am seeing the "Success" message on the console. When am trying to echo this sssion variable in another page, this is shown empty.

Any help is greatly appreciated.

Session on your local page will not exist until you reload the page because the session is controlled on the server-side. — Jay Blanchard
– Jay Blanchard, Commented Oct 12, 2016 at 13:16

Mohit Tanwani · Accepted Answer · 2016-10-12 13:18:28Z

3

Please use session_start() on the first line of your PHP code to make the session works for you for that page.

You might have following problems

Might be missing session_start()
You might getting blank values on $_POST

Do the debug for ajax call and don't forget to check print_r($_POST) has values in success or not.

answered Oct 12, 2016 at 13:18

Mohit Tanwani

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8 Comments

user168983 Over a year ago

modifid with session_start(); still no luck

Mohit Tanwani Over a year ago

Try with change POST instead of post and make sure that you're getting data in $_POST

user168983 Over a year ago

console.log(data) is returning empty. still confused why php is not returning data

Mohit Tanwani Over a year ago

is your url is right ? what print_r($_POST) this gives ?

Mohit Tanwani Over a year ago

So everything is ok for you now ?

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