PHP add to variable name

Question

Is it possible to add or concatenate something into a variable name in a PHP variable? For example:

for($g = 7; $g <= 10; $g++){
    for($i = 0; $i <= 4; $i++){
        $counter = $g - 7;
        if($i != $counter){
            continue;
        } else {
            $grade.[$g] = $grades[$i];
        }
    }
}

I want this to happen:

$grade7 = 0
$grade8 = 1
$grade9 = 2
$grade10 = 3

For such purposes use arrays

u_mulder
– u_mulder

2016-10-13 08:51:23 +00:00
Commented Oct 13, 2016 at 8:51 — u_mulder
– u_mulder, Commented Oct 13, 2016 at 8:51
$$ is your answer

Kinshuk Lahiri
– Kinshuk Lahiri

2016-10-13 08:53:46 +00:00
Commented Oct 13, 2016 at 8:53 — Kinshuk Lahiri
– Kinshuk Lahiri, Commented Oct 13, 2016 at 8:53

Murad Hasan · Accepted Answer · 2016-10-13 08:57:19Z

1

Concatenates the $g with grade and make this value a variable by adding a $ sign at the starting line...

The example given below:

for($g = 7; $g <= 10; $g++){
    for($i = 0; $i <= 4; $i++){
        $counter = $g - 7;
        if($i != $counter){
            continue;
        } else {
            ${"grade".$g} = $grades[$i];
        }
    }
}

echo $grade7; // 0
echo $grade8; // 1
echo $grade9; // 2
echo $grade10;// 3

answered Oct 13, 2016 at 8:57

Murad Hasan

9,5932 gold badges23 silver badges43 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

aronccs Over a year ago

Exactly what I have been looking for. Thank you

Mihai Matei · Accepted Answer · 2016-10-13 08:55:32Z

1

One solution would be to create the variables dynamically:

for ($g = 7; $g <= 10; $g++) {
    for ($i = 0; $i <= 4; $i++) {
        $counter = $g - 7;
        if ($i == $counter) {
            ${'grade' . $g} = $grades[$i];
        }
    }
}

answered Oct 13, 2016 at 8:55

Mihai Matei

24.3k5 gold badges34 silver badges50 bronze badges

Comments

OverSu · Accepted Answer · 2016-10-13 08:52:42Z

0

You should use ARRAY instead of your method. :)

Try to look at variable named like "$$".

EDIT: Maybe something like

var $array = array();
for($g=7; $g<=10; $g++)
{
    for($i=0; $i<=4; $i++)
    {
        $counter = $g - 7;
        if($i != $counter) continue;
        else $array[$grade.[$g]] = $grades[$i];
    }
}

answered Oct 13, 2016 at 8:52

OverSu

1101 silver badge9 bronze badges

Comments

HuntsMan · Accepted Answer · 2016-10-13 08:53:45Z

0

 $data = new Array();
 for($g = 7; $g <= 10; $g++){
        for($i = 0; $i <= 4; $i++){
            $counter = $g - 7;
            if($i != $counter){
                continue;
            } else {
                $data[$grade.[$g]] = $grades[$i]);
            }
        }
    }

answered Oct 13, 2016 at 8:53

HuntsMan

8126 silver badges16 bronze badges

1 Comment

pguetschow Over a year ago

$data = array(); would also be possible

Collectives™ on Stack Overflow

PHP add to variable name

4 Answers 4

1 Comment

Comments

Comments

1 Comment

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

1 Comment

Comments

Comments

1 Comment

Your Answer

Sign up or log in

Post as a guest

Related