Sort Array of objects in Java [duplicate]

Question

Currently I am working on a contact manager project where I have a contactMgr class, and a contact class within the contactMgr class that stores a contacts info.

To start out the program, I create a contactMgr array with 20 indices. Then, when I create a contact, that includes name, email and phone number, I then store it in the contactMgr array. All of the fields for the contact object are stored as Strings.

How can I sort the contact objects in the contactMgr array alphabetically by name?

Let ContractMgr implement Comparable<ContractMgr>, then call Array.sort(yourContractMgrArray). — Turing85
– Turing85, Commented Oct 15, 2016 at 23:54

Zbynek Vyskovsky - kvr000 · Accepted Answer · 2016-10-15 23:58:21Z

0

You can use Arrays.sort(T[], Comparator<T>) for this:

ContactMgr[] contacts = ...;
Arrays.sort(contacts, (ContactMgr left, ContactMgr right)
    -> left.getName().compareTo(right.getName())
);

Or if the ContactMgr already implements Comparable interface and it works as comparing the names, you can call Arrays.sort(contact) with default comparator.

edited Oct 15, 2016 at 23:58

answered Oct 15, 2016 at 23:56

Zbynek Vyskovsky - kvr000

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1 Comment

William Over a year ago

So I tried implementing the Comparable interface with the Contact class, but it won't let me pass in Contact as an argument to Arrays.sort.

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