Undefined index: when reading array values - PHP

Question

This is the var_dump of my array (var_dump $syn3):

array(1) { 
     ["@attributes"]=> 
     array(2) { 
         ["date"]=> string(10) "Sun 16 Oct" 
         ["time"]=> string(5) "21:45" 

     } 
}

I am trying to pull out date and time:

foreach($array2 as $syn3) {     
    $datemovie = $syn3['@attributes']['date'];
    $timemovie = $syn3['@attributes']['time'];

}

The above results in

PHP Notice: Undefined index: @attributes in

I don't get it - this should have worked. Where is my mistake?

I dont think @ is the problem. eval.in/661838. What is the actual array ($array2)? — Sougata Bose
– Sougata Bose, Commented Oct 17, 2016 at 10:31

LF-DevJourney · Accepted Answer · 2016-10-17 10:49:56Z

1

<?php
$array = array("@attributes"=>array("date"=>'Sun 16 Oct', "time"=>'21:45'));
var_dump($array);
$datemovie = $array['@attributes']['date'];
$timemovie = $array['@attributes']['time'];

answered Oct 17, 2016 at 10:49

LF-DevJourney

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Comments

Stephan Bauer · Accepted Answer · 2016-10-17 11:13:05Z

1

foreach($array2 as $syn3)

$syn3 here has been changed to the first element of $array2

Use another name.

edited Oct 17, 2016 at 11:13

Stephan Bauer

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answered Oct 17, 2016 at 10:46

LC2013

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1 Comment

Cody Raspien Over a year ago

Surely, renaming wouldn't work. Do you mean renaming inside the for each loop?

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