session's variables values retrieving in _LayoutPartial in asp.net mvc

Question

I'm filling values to a session's like following to retrive those in _LayoutPartial view

if (userdata != null)
{
    Session["userdata"] = new SampleViewModel { FirstName = userdata.UserFirstName, LastName = userdata.UserLastName };
    FormsAuthentication.SetAuthCookie(loginmodel.UserName, false);
    return RedirectToAction("Dashboard", "Home", new { username = loginmodel.UserName });
}

I want to retrive those values in _LayoutPartial View , So I tried somethin like following

<a class="sa">
    (@Session["userdata"] as ProjectName.Models.SampleViewModel).FirstName 
    (@Session["userdata"] as ProjectName.Models.SampleViewModel).LastName
</a>

But this is not retrieving data properly . In this _LoginPartial I'm not Referencing any model also

user3559349 · Accepted Answer · 2016-10-18 05:09:21Z

1

You have your parenthesis in the wrong spot, and you need a double set - one for the casting (inner set) and one for the razor execution (outer set). It needs to be

@((Session["userdata"] as ProjectName.Models.SampleViewModel).Name)

answered Oct 18, 2016 at 5:09

user3559349

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4 Comments

kez Over a year ago

Is that the my approach optimum way , show the user.FirstName , user.LastName on _LayoutPartial if I'm not following any membership providers

user3559349 Over a year ago

Personally I would have a base view model that is used in the view and I would be adding the values to the FormAuthenticationTicket, rather than using Session, but there is nothing wrong with what your doing

kez Over a year ago

If this @((Session["userdata"] as ProjectName.Models.SampleViewModel).Name) getting null , when view loading then run time error is occurring , how to avoid that and store this inside a variable to reuse easily ?

user3559349 Over a year ago

You need to check for null first - e.g. @{ var userData = Session["userdata"] as ProjectName.Models.SampleViewModel; } then @if(userData != null} { <a class="sa">@userData.FirstName @userData.FirstName</a> }

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