Java regex pattern matching

Question

I want to match the following string pattern for my code. the string value is fixed as below:

630512-07-5847

Pattern p = Pattern.compile("(\\d{6,6})-(\\d{2,2})-(\\d{4,4})");

I've tried the code above, however, when it has more number such as "630512312-07-5847" , it still return true

Scary Wombat · Accepted Answer · 2016-10-20 02:31:16Z

2

try

^\\d{6}-\\d{2}-\\d{4}$

This will make sure the if the match begins and end with the entire string,

so

630512-07-5847 - OK
630512-07-58472 - NOT OK
1630512-07-5847 - NOT OK

answered Oct 20, 2016 at 2:31

Scary Wombat

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7 Comments

hiboss Over a year ago

Thank you, your method works, however, when i use Matcher.find() twice, it return me two different result.

hiboss Over a year ago

for example : System.out.println( m.find() ) ; return m.find();

Scary Wombat Over a year ago

The first find will return true, the second one will return false

hiboss Over a year ago

yes, i am wondering why this would happened, since I've pass the pattern and value to matcher

kjsebastian Over a year ago

@hiboss The docs explains the why. docs.oracle.com/javase/7/docs/api/java/util/regex/…

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Dale · Accepted Answer · 2016-10-20 02:42:25Z

1

Are you tried actually?

public class Test {
    public static void main(String[] args) {
        System.out.println("630512312-07-5847".matches("(\\d{6,6})-(\\d{2,2})-(\\d{4,4})"));
    }
}

the result is false, bad question

answered Oct 20, 2016 at 2:42

Dale

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1 Comment

hiboss Over a year ago

you answer works good too. I am using the Pattern and Matcher library for my string matching though. didn't know such method works without the library

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