Move Array element using PHP/Laravel

Question

I am trying to move 2 elements in my array. When I output the current array, this is my result:

 array:["Date" => "2016-09-25"
      "emp" => "12345  "
      "work" => "coding"
      "Hours" => "6.00"
      "L" => "L"
      "IBEW" => "IBEW"
      ]

What I'm trying to achieve is to move the two values (L and IBEW) to the second and third place, like this:

array:["Date" => "2016-09-25"
      "emp" => "12345"
      "L" => "L"
      "IBEW" => "IBEW"
      "work" => "coding"
      "Hours" => "6.00"
       ]

How is this possible?

for your expected output because arrays comes according to fields saved in table of database — Naveen Kumar
– Naveen Kumar, Commented Oct 21, 2016 at 8:19
"L" => "L" "IBEW" => "IBEW" these two columns are not in database this vitrual columns we are pushing in array — MGS
– MGS, Commented Oct 21, 2016 at 8:21
are you using hidden fields, are you using dynamic or static — Naveen Kumar
– Naveen Kumar, Commented Oct 21, 2016 at 8:28

nanocv · Accepted Answer · 2016-10-21 10:31:16Z

2

Here you have a working and tested answer for that.

You just have to change $output to the right variable name.

foreach ($output as &$outputItem) {

  // Here we store the elements to move in an auxiliar array
  $arrayOfElementsToMove = [
      "L" => $outputItem["L"],
      "IBEW" => $outputItem["IBEW"]
  ];

  // We remove the elements of the original array
  unset($outputItem["L"]);
  unset($outputItem["IBEW"]);

  // We store the numeric position of CostCode key
  $insertionPosition = array_search("CostCode", array_keys($outputItem));

  // We increment in 1 the insertion position (to insert after CostCode)
  $insertionPosition++;

  // We build the new array with 3 parts: items before CostCode, "L and IBEW" array, and items after CostCode
  $outputItem = array_slice($outputItem, 0, $insertionPosition, true) +
          $arrayOfElementsToMove +
          array_slice($outputItem, $insertionPosition, NULL, true);
}

edited Oct 21, 2016 at 10:31

answered Oct 21, 2016 at 8:25

nanocv

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6 Comments

nanocv Over a year ago

@Murali Then it would be great if you edit your question to add the code of the database connection, just for us to check the method you are using and the field names.

MGS Over a year ago

i was attached my screen shot image. without the parent array your answer is correct but hear parent array is coming that is the pblm for me

nanocv Over a year ago

@Murali Edited my answer. Hope it helps!

MGS Over a year ago

only one record your answer is woking fine.. but i have more records in your answer is taking last record

nanocv Over a year ago

@Murali In the picture showed before you edited the question there was a main array with two associative arrays inside. That main array is my $output variable. The foreach loop goes through all the arrays inside and swap the keys to the order you wanted.

|

GThamizh · Accepted Answer · 2016-10-21 11:03:05Z

For Example Have append the 'L' AND 'IDEW' key values after the work key,

<?php

# For Example Have append the 'L' AND 'IDEW' key values after the work key
$main_array = [
"Date" => "2016-09-25",
"emp" => "12345  ",
"work" => "coding",
"Hours" => "6.00",
"L" => "L",
"IBEW" => "IBEW"
];

$split_values = array("L"=>$main_array["L"], "IBEW"=>$main_array["IBEW"]);

unset($main_array['L']);
unset($main_array['IBEW']);

$array_decide = 0;

foreach($main_array as $k=>$v){
    if ($array_decide == 0){
        $array_first[$k] = $v;
    } elseif ($array_decide == 1) {
        $array_final[$k] = $v;
    }
    if ($k=='work'){
        $array_final = array_merge($array_first,$split_values);
        $array_decide = 1;
    }
}

echo "<pre>";
print_r($array_final);
echo "</pre>";

/*OUTPUT:
Array
(
    [Date] => 2016-09-25
    [emp] => 12345  
    [work] => coding
    [L] => L
    [IBEW] => IBEW
    [Hours] => 6.00
)*/


?>

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