i have the following regex which is working fine in JAVA code
[A-Za-z0-9!#$%&'*+/=?^_`{|}~-]+(?:\\.[A-Za-z0-9!#$%&'*+/=?^_`{|}~-]+)*@(?:[A-Za-z0-9](?:[A-Za-z0-9-]*[A-Za-z0-9])?\\.)+[A-Za-z0-9](?:[A-Za-z0-9-]*[A-Za-z0-9])?
but same is not working in the Java script
can any one please tell me the solution for this
thanks Sunny Mate
I'd put the last hyphen from those sets as the first character:
Before:
[A-Za-z0-9!#$%&'*+/=?^_`{|}~-]
After:
[-A-Za-z0-9!#$%&'*+/=?^_`{|}~]
The hyphen will allow a range of characters. It will be treated as hyphen if it is the first character of the set. Else, it could mean "from '~' until ']'"
But still, it's hard to answer precisely without a precise question.
EDIT:
I've tested this expression on a simple JavaScript RegEx tester, and I discovered it is meant to match e-mail addresses. It worked for me after I replaced the double-backslashes \\ by single ones \.
In JavaScript, the following two should work the same:
var re = /a\.c/;
var re = new RegExp("a\\.c");
But the second one requires double back-slashes because it is enclosed in a string, which requires escaping. If all else fails, check Mozilla Developer Center.
But, again, it's impossible to give a precise answer without a precise question. What's more, when you try to improve your question, it's more likely that you will find your bug.
Regular Expression is slightly different in each programming language, please reference the manual/document.
