BASH–Getting results from PHP

Question

I am trying to retrieve some output from php, using bash. So far I have this:

CODE="<?php chdir('$WWW');" # $WWW should be interpolated

CODE+=$(cat <<'PHP' # no interpolation for the rest of the code
    require_once('./settings.php'); 

    $db = $databases['default']['default'];

    $out = [
        'user=' . $db['username']
        //more here
    ];

    echo implode("\n", $out)
PHP)

echo $CODE    

#RESULT=$($CODE | php)

#. $RESULT

All in all I am having trouble with the String interpolation. Right now I get:

line 10: <?php: command not found

So how can I properly escape the string such that the whole php code?

All in all, the PHP should generate output like that:

key=value
key2=value2

which can be "sourced" by the bash

Thanks in Ahead!

Ruslan Osmanov · Accepted Answer · 2016-11-07 12:07:17Z

2

Using Here String

php <<< "$CODE"

Using Pipe

echo "$CODE" | php

If you want to store the output into a variable, use the command substitution:

result=$(php <<< "$CODE")
result=$(echo "$CODE" | php)

edited Nov 7, 2016 at 12:07

answered Nov 7, 2016 at 12:01

Ruslan Osmanov

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1 Comment

philipp Over a year ago

This is the more complete answer, so I will choose that one!

Ko Cour · Accepted Answer · 2016-11-07 11:59:41Z

2

This is wrong: RESULT=$($CODE | php) - shell variable can't be passed like that, it attempts to run $CODE as a command.

Instead you can do RESULT=$(echo "$CODE" | php) or RESULT=$(php <<<"$CODE")

answered Nov 7, 2016 at 11:59

Ko Cour

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Comments

cb0 · Accepted Answer · 2016-11-07 12:06:32Z

0

I think you have 2 errors in here:

error in your here-doc block. No need for ' around PHP.
You need to escape the $ in your PHP code, or otherwise it will be expanded by bash.

Try:

#!/bin/bash

CODE="<?php chdir('$WWW');" # $WWW should be interpolated

CODE+=$(cat << PHP # no interpolation for the rest of the code
    //require_once('./settings.php'); 

    \$db = "foo";

    \$out = [
        'user=' . \$db
        //more here
    ];

    echo implode("\n", \$out)
PHP
)

echo $CODE

This will print out:

<?php chdir("/tmp"); //require_once('./settings.php'); $db = "foo"; $out = [ 'user=' . $db //more here ]; echo implode("\n", $out);

Which can be evaluated in php.

answered Nov 7, 2016 at 12:06

cb0

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2 Comments

Ko Cour Over a year ago

Having ' around PHP in the Heredoc statement is a good thing. It means that the content won't be subjected to expansion of special characters - therefore there will be no need to add backslashes before $.

cb0 Over a year ago

Thanks for that info. I wasn't aware of that. One never stops learning.

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