Check if value is in array PHP (easy?)

Question

I think I have a very easy question, but I am stuck anyway. I want to check if the value is in an array, and if it is, i want to change the variable value.

$admin_is_menu = "about";
$test = array();
$test = [
["Name" => "About","alias" => "about"],
["Name" => "Test", "alias" => "test"],
];
if(in_array($admin_is_menu, $test)){
    $admin_is_menu = "true";
}
echo $admin_is_menu;

In the code above, it should output the echo "true", since "about" is in the array. But is unfortunally does not work.

What am I doing wrong?

and seeing an answer posted using the same coding, @cske should be posting an answer for it, or at the very least; given some credit. — Funk Forty Niner
– Funk Forty Niner, Commented Nov 7, 2016 at 13:01
I think I am doing some small thing wrong yes, cske had the right answer indeed! Unfortunally i cannot upvote his post , nor an unposted answer :( — Saypontigohe
– Saypontigohe, Commented Nov 7, 2016 at 13:08

Nikhil Vaghela · Accepted Answer · 2016-11-07 12:54:58Z

1

Try array_column to get all array value.

$admin_is_menu = "about";
$test = array();
$test = [
["Name" => "About","alias" => "about"],
["Name" => "Test", "alias" => "test"],
];
if(in_array($admin_is_menu, array_column($test,'alias'))){
    $admin_is_menu = "true";
}
echo $admin_is_menu;

DEMO

answered Nov 7, 2016 at 12:54

Nikhil Vaghela

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Comments

Kevin Kopf · Accepted Answer · 2016-11-07 13:03:35Z

1

@cske pointed out in the comment how to do it. Here's a small explanation for that as well.

You should use array_column. In this case array_column($test, "alias") will return a new array:

array(2) {
  [0]=>
  string(5) "about"
  [1]=>
  string(4) "test"
}

Now, you check within it with in_array:

in_array($admin_is_menu, array_column($test,'alias'))

and this will return true

edited Nov 7, 2016 at 13:03

answered Nov 7, 2016 at 12:57

Kevin Kopf

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