how to parse string into json object javascript [duplicate]

Question

I'm trying to parse this string into a JSON:

 "{'firstname':'Jesper','surname':'Aaberg','phone':'555-0100'}"

I'm doing it like so:

var strJSON = "{'firstname':'Jesper','surname':'Aaberg','phone':'555-0100'}";
console.log(JSON.parse(strJSON));

But I get the error message:

VM652:1 Uncaught SyntaxError: Unexpected token ' in JSON at position 1 at JSON.parse ()

Does anybody know what am I missing and how can i solve it?

The JSON is invalid. You should use double quotes in it, not single quotes. — VLAZ
– VLAZ, Commented Nov 10, 2016 at 13:28

Rajesh Dixit · Accepted Answer · 2016-11-10 13:30:06Z

4

You can replace single quotes to double quotes and parse it.

var str =  "{'firstname':'Jesper','surname':'Aaberg','phone':'555-0100'}";

var o = JSON.parse(str.replace(/\'/g, "\""));
console.log(o)

answered Nov 10, 2016 at 13:30

Rajesh Dixit

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1 Comment

Emmanuel Villegas Over a year ago

thanks man! that what i'm looking for

laurent · Accepted Answer · 2016-11-10 13:34:04Z

3

Single quotes are not valid for strings, you need to use double quotes instead:

var strJSON = '{"firstname":"Jesper","surname":"Aaberg","phone":"555-0100"}';

edited Nov 10, 2016 at 13:34

answered Nov 10, 2016 at 13:29

laurent

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2 Comments

Sean Cogan Over a year ago

For clarity, I'd wrap your answer in single quotes, since he does want to parse a string of JSON. I couldn't actually suggest an edit since it was only two characters.

laurent Over a year ago

Good point, I made the change.

Lucas Gabriel Sánchez · Accepted Answer · 2016-11-10 13:31:10Z

1

Just change your string:

"{'firstname':'Jesper','surname':'Aaberg','phone':'555-0100'}"

to:

'{"firstname":"Jesper","surname":"Aaberg","phone":"555-0100"}'

JSON only supports double-quotes

answered Nov 10, 2016 at 13:31

Lucas Gabriel Sánchez

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Comments

Atul Sharma · Accepted Answer · 2016-11-10 13:33:01Z

0

var str = '{"firstname":"Jesper","surname":"Aaberg","phone":"555-0100"}';

console.log(JSON.parse(str));

Use this.

answered Nov 10, 2016 at 13:33

Atul Sharma

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