Convert C-Style String to an Integer Array

Question

I have 2 functions, they are called SplitInt(unsigned int x) and SplitChar(char x[])

SplitInt takes in any positive integer, such as 12345, and puts each digit into an integer array, but backwards. So for SplitInt(12345) the array would look like this:

array[0] = 5
array[1] = 4
array[2] = 3
array[3] = 2
array[4] = 1

SplitChar() is supposed to do the same thing but take in a C-Style string, such as "12345".

How would I separate the individual digits and send them into an integer array? I am not allowed to use string class.

Thanks!

What have you tried so far? Also, remember that a c-style string is just a char array and that 1 = '1' - '0' — Eli Sadoff
– Eli Sadoff, Commented Nov 16, 2016 at 4:23
Nothing to be honest. I only understand how to do it with integers being passed in because I just used modulus to separate the number to individual digits. For the string, I know conceptually what I wanna do. "123456789" gets passed in, I look at the first character, send it into the array, then second character, send it into array, and so on. Don't know the syntax to get that done though. — zubi
– zubi, Commented Nov 16, 2016 at 4:58
Is my function declaration correct? What I want to be able to do is this: SplitChar("123456789"); — zubi
– zubi, Commented Nov 16, 2016 at 5:01

Flanker · Accepted Answer · 2016-11-17 14:33:48Z

1

#define MAX_STR_LENGTH 100

int array[MAX_STR_LENGTH];

int SplitChar(char x[])
{
    int len = strlen( x );

    if ( len > MAX_STR_LENGTH )
        return -1;

    int i = 0;

    while ( i < len )
    {
        array[len-i-1] = x[i] - '0';
        i++;
    }

    return len;
}

Returns the length of the string or -1 if too long.

edited Nov 17, 2016 at 14:33

answered Nov 16, 2016 at 4:38

Flanker

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2 Comments

Flanker Over a year ago

@acraig5075 Thanks, fixed

Quentin Over a year ago

If you're going to provide free code, at least make it behave better than triggering UB when the input is too big...

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