Passing array through function with Key names php?

Question

I'm trying to pass an array that has defined keys into a function parameter, but when I call the function it creates it's own set of numeric keys for the array. How can I make it use the same keys?

<?php

$param = [
"foo" => "bar",
"bar" => "foo",
];

function amazonRequest($AmazonQuery) {
    $url = array();
    foreach ($AmazonQuery as $key => $val) {

    $key = str_replace("%7E", "~", rawurlencode($key));
    $val = str_replace("%7E", "~", rawurlencode($val));
    $url[] = "{$key}={$val}";

    print_r($url);
 }
}

amazonRequest($param);
print_r($param);

$url[$key] = "{$key}={$val}"; perhaps? If I understood your question correctly. — M. Eriksson
– M. Eriksson, Commented Nov 16, 2016 at 16:02

Blackbam · Accepted Answer · 2016-11-16 17:16:14Z

1

You are autonumbering an empty array:

$url[] = "{$key}={$val}";

Of course it will be numbered starting from 0. You can use $url[$key] = "{$key}={$val}"; if you want the keys to be the same.

edited Nov 16, 2016 at 17:16

Blackbam

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answered Nov 16, 2016 at 16:07

Mike Aron

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M. Eriksson · Accepted Answer · 2016-11-16 16:08:10Z

1

When you add new items to an array using: $array[] = "something", it will add an indexed key [0 => 'something', ...] always starting at 0.

If you want to add a new item with an associative key (non sequenced or string) you need to define the key name:

// Since you get the key in your foreach loop, just add it like this:
$url[$key] = "{$key}={$val}";

The new $url-array should now look like:

[
    "foo" => "foo=bar",
    "bar" => "bar=foo"
]

answered Nov 16, 2016 at 16:08

M. Eriksson

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