Bash: replace text in nth line of file with nth index of array

Question

Trying to replace MAC Addresses in a flat file. In the code below, the addresses are successfully mapping to the array. I've tried to use a counter to increment the array index on each loop, with the intent of replacing the address on line n with the nth address in the array.

The sed block effectively replaces the addresses, but only with the entry at array index 0.

mapfile -t Arr1 < <(text processing commands)

i=0  
while read line 
do
  sed -E "s/([[:xdigit:]]{1,2}:){5}[[:xdigit:]]{1,2}/${Arr1[$i]}/"
  ((i++))
done < $macFile

Example input/output/expected output?

Oleg Andriyanov
– Oleg Andriyanov

2016-11-16 20:43:16 +00:00
Commented Nov 16, 2016 at 20:43 — Oleg Andriyanov
– Oleg Andriyanov, Commented Nov 16, 2016 at 20:43

ruakh · Accepted Answer · 2016-11-16 20:51:13Z

1

The problem is that sed is reading from standard input, so instead of reading the contents of the $line variable, it's reading the contents of the file designated by $macFile (except the first line, which has already been grabbed by read).

To fix this, add <<< "$line" to the end of your sed command.

answered Nov 16, 2016 at 20:51

ruakh

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