PHP can't retrieve JSON from ajax call

Question

here's my JS code:

var person = [];
    person[0] = "John";
    person[1] = "Doe";
    person[2] = 46;
    var myData = JSON.stringify(person);
    $.ajax({
        type: "POST",   
        url: "test.php",
        dataType : "text", 
        contentType: "application/json; charset=utf-8",
        data: myData,
        success: function(answer) {
            alert(answer);
        },
        complete: function() {
        },
        error: function(jqXHR, errorText, errorThrown) {
            alert(jqXHR+" - "+errorText+" - "+errorThrown);
        }
    });

And here's php:

if(isset($_POST['myData']))
{
 echo "ok";
}
else
{
 echo "not_ok";
}
?>

And it always returns "not_ok". Why my PHP code can't retrieve JSON? What I'am doing wrong? Could anyone explain it to me?

You should use json_encode(); !

Saumya Rastogi
– Saumya Rastogi

2016-11-17 13:13:03 +00:00
Commented Nov 17, 2016 at 13:13 — Saumya Rastogi
– Saumya Rastogi, Commented Nov 17, 2016 at 13:13
data: {myData : myData},

adeneo
– adeneo

2016-11-17 13:14:08 +00:00
Commented Nov 17, 2016 at 13:14 — adeneo
– adeneo, Commented Nov 17, 2016 at 13:14

Gopal Joshi · Accepted Answer · 2016-11-17 13:32:43Z

1

Try below

dataType : "json" : tells jQuery that you want it to parse the returned JSON

json_encode() : PHP function encodes array in json format.

JavaScript

var person = [];
person[0] = "John";
person[1] = "Doe";
person[2] = 46;

$.ajax({
    type: "POST",   
    url: "test.php",
    dataType : "json",  // Set datatype json
    data: {myData : person}, // Request Parameters
    success: function(answer) {
        console.log(answer); // JSON Response
    },
    complete: function() {
    },
    error: function(jqXHR, errorText, errorThrown) {
        alert(jqXHR+" - "+errorText+" - "+errorThrown);
    }
});

PHP

<?php
    if(isset($_POST['myData'])){
        $status = "ok";
    }
    else
    {
        $status = "Not Ok";
    }
    echo json_encode(array("status" => $status));
    exit;
?>

Output

Object {status: "ok"}

edited Nov 17, 2016 at 13:32

answered Nov 17, 2016 at 13:16

Gopal Joshi

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7 Comments

Petrus Over a year ago

It's me again. I was wrong.... it returns "Not ok". Dunno why, i copied and pasted your code instead of mine.

Gopal Joshi Over a year ago

Pls write print_r($_POST); before if(isset($_POST['myData'])){ and show us output

Petrus Over a year ago

Array ( ) {"status":"Not Ok"}

Gopal Joshi Over a year ago

Please replace data: {'myData' : person}, with data: {myData : person}, and let us know output

Petrus Over a year ago

Weird. After that change it works: "Object { status: "ok" }". Until i added "print_r($_POST);" in php, cuz after that alert occurs: "[object Object] - parsererror - SyntaxError: JSON.parse: unexpected character at line 1 column 1 of the JSON data"

|

madalinivascu · Accepted Answer · 2016-11-17 13:12:53Z

0

You need some keys to get your data from the post/get variables

 data:{firstname:"John",lastname:"Doe",age:45},

php:

$_POST['firstname']

or

data:{data:["John","Doe",45]},

if you really want a array

 $_POST['data']

answered Nov 17, 2016 at 13:12

madalinivascu

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Comments

Ima · Accepted Answer · 2016-11-17 13:21:12Z

0

You are converting your array to string in json format without any name. But you can post array in ajax post, you dont need to stringify it. you can pass your array as it is

data: {myData: person},



var person = [];
    person[0] = "John";
    person[1] = "Doe";
    person[2] = 46;

$.ajax({
    type: "POST",   
    url: "test.php",
    dataType : "text", 
    contentType: "application/json; charset=utf-8",
    data: {myData: person},
    success: function(answer) {
        alert(answer);
    },
    complete: function() {
    },
    error: function(jqXHR, errorText, errorThrown) {
        alert(jqXHR+" - "+errorText+" - "+errorThrown);
    }
});

answered Nov 17, 2016 at 13:21

Ima

1,10912 silver badges26 bronze badges

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