PHP loop over array keys and return value

Question

I am trying to loop over the keys of an array and return the value when that key matches with a variable. But what I am doing just doesn't seem to make much sense.

public function check($variable)
{
    $result = 0;

    $amount = array(
        3 => 10,
        4 => 20,
        5 => 50
        );

    foreach ($amount as $a) {
        if ($a == $variable) {
            $result = $a[$amount];
        }
    }

    return $result;
}

At this point I am not even sure anymore if what I am doing is right :p

Anyone who could help me out?

Many thanks in advance!

hmmm.... I'm betting it should be: $result = $a... but its unclear what you want.... — barudo
– barudo, Commented Nov 18, 2016 at 9:22
You use of keys and values is very confusing: What is the input and matching output? Some examples would help. — jeroen
– jeroen, Commented Nov 18, 2016 at 9:24

user2693928 · Accepted Answer · 2016-11-18 09:23:08Z

2

public function check($variable)
{
    $result = 0;

    $amount = array(
        3 => 10,
        4 => 20,
        5 => 50
    );

    if (isset($amount[$variable])) {
        $result = $amount[$variable];
    }

    return $result;
}

answered Nov 18, 2016 at 9:23

user2693928

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Comments

Kanishka Panamaldeniya · Accepted Answer · 2016-11-18 09:24:52Z

0

public function check($variable)
{
    $result = 0;

    $amount = array(
        3 => 10,
        4 => 20,
        5 => 50
        );

    foreach ($amount as $k=>$v) {
        if ($k == $variable) {
            $result = $v;
        }
    }

    return $result;
}

answered Nov 18, 2016 at 9:24

Kanishka Panamaldeniya

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Comments

Werner · Accepted Answer · 2016-11-18 09:30:38Z

0

function check($variable)
{
    $result = 0;
    $amount = array(
        3 => 10,
        4 => 20,
        5 => 50
        );


    foreach ($amount as $a) {
        if ($a == $variable) {
            $result = $a;
        }
    }

    return $result;
}

Basically the line assigning $a to $result wasn't in order. That was all that needed fixing. It now either returns 0 or the $variable if it's in the list. Frankly You were very close to the right code...

answered Nov 18, 2016 at 9:30

Werner

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Comments

Mihai Matei · Accepted Answer · 2016-11-18 09:32:37Z

0

You don't need so much logic.. I think you don't need a function for that too, but here it is:

var_dump(check(4));

function check($variable)
{
    $amount = array(
        3 => 10,
        4 => 20,
        5 => 50
    );

    return isset($amount[$variable]) ? $amount[$variable] : 0;
}

As I can see this is a method inside a class.. it would be better to see all the methods from that class

edited Nov 18, 2016 at 9:32

answered Nov 18, 2016 at 9:25

Mihai Matei

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2 Comments

Frank Lucas Over a year ago

How can I do this without a function?

Frank Lucas Over a year ago

It's a bit too much to show I want to do this check as part of an other rather big function

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