Conditionally getting json data using java

Question

below is my code where Im trying to check id id =101 and getting the name= Pushkar assosiated with the id=101.But the code is not working as expected.

import org.json.simple.JSONArray;
import org.json.JSONException;
import org.json.simple.JSONObject;
import org.json.simple.parser.JSONParser;
import org.json.simple.parser.ParseException;

public class A6 {
public static void main(String[] args) throws ParseException, JSONException{

    String out1="{\"Employee\":[{\"id\":\"101\",\"name\":\"Pushkar\",\"salary\":\"5000\"},{\"id\":\"102\",\"name\":\"Rahul\",\"salary\":\"4000\"},{\"id\":\"103\",\"name\":\"tanveer\",\"salary\":\"56678\"}]}";

//System.out.println(out1);
JSONParser parser=new JSONParser();
JSONObject obj=(JSONObject)parser.parse(out1);
//System.out.print(obj);
JSONArray jarr=(JSONArray)obj.get("Employee");
//System.out.print(jarr);
for (int i=0;i<jarr.size();i++)
{ 


    JSONObject jobj=(JSONObject)jarr.get(i);
    String ID1=(String)jobj.get("id");
    System.out.println(ID1);
    if(ID1!=null && out1.equals(ID1))
    {
    System.out.println("NAME"+jobj.get("name"));
    }



}
}}

check your if condition if(ID1!=null && out1.equals(ID1)) here out1 and ID1 might have different values hence your condition will not true — Onkar
– Onkar, Commented Nov 21, 2016 at 7:47

Alexander S · Accepted Answer · 2016-11-21 07:59:17Z

1

why do you compare out1 with ID1? Either you want to check if out1 contains ID1 (which is not very meaningfull, as you retrieve ID1 from out1) or you want to verify that ID1 equals 101. In that case you would rather want to say something like:

if(ID1!=null && "101".equals(ID1))
    {
    System.out.println("NAME"+jobj.get("name"));
    }

answered Nov 21, 2016 at 7:59

Alexander S

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Comments

ROOT · Accepted Answer · 2016-11-21 07:49:18Z

1

Try to change if condition like this:

if(ID1!=null && out1.contains(ID1))
    {
    System.out.println("NAME"+jobj.get("name"));
    }

Thanks.

answered Nov 21, 2016 at 7:49

ROOT

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