format array to output in node.js

Question

var toFormat = [[1, "one", "unu"], [2, "two", "du"], [3, "three", "tri"], [4, "four", "kvar"]];

I need to output array toFormat so it should look like this:

1 (one)
2 (two)
3 (three)
4 (four)

(The third element of every sub-array is not used) How to do that?

EDIT: The loop is here

var res = []; 
for(var i=0;i<toFormat.length;i++){
    res.push(toFormat[i][1]+" ("+toFormat[i][2]+")");
}
console.log(res.join("\n"))

var res = []; for(var i=0;i<toFormat.length;i++){res.push(toFormat[i][1]+" ("+toFormat[i][2]+")");}console.log(res.join("\n")); — lithium_js
– lithium_js, Commented Nov 21, 2016 at 20:20
And the body of your for loop?, also edit your question with this not in a comment... — Zach M.
– Zach M., Commented Nov 21, 2016 at 20:22
You are using 1 and 2 as the indexes and not 0 and 1. jsfiddle.net/5aqzkeox — Zach M.
– Zach M., Commented Nov 21, 2016 at 20:27

score 5 · Accepted Answer · 2016-11-21 20:30:16Z

5

const toFormat = [
   [1, "one",   "unu"], 
   [2, "two",   "du"], 
   [3, "three", "tri"], 
   [4, "four",  "kvar"]];

const result = toFormat.map(([val, string]) => `${val} (${string})`).join('\n');

console.log(result);

edited Nov 21, 2016 at 20:30

answered Nov 21, 2016 at 20:24

user663031

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2 Comments

WitVault Over a year ago

In this one liner solution there is quite good use of es6 features :)

Eli Sadoff Over a year ago

Nice use of interpolation!

Eli Sadoff · Accepted Answer · 2016-11-21 20:53:35Z

1

There are a ton of ways this can be done. I'd personally recommend using a for...of loop, like this

// defining the array to loop over
const toFormat = [
  [1, 'one', 'unu'],
  [2, 'two', 'du'],
  [3, 'three', 'tri'],
  [4, 'four', 'kvar']
];

for (let i of toFormat) {
  console.log(i[0] + " (" + i[1] + ")");
}

Of course, if you want this as a string instead of being printed you can do this instead

// defining the array to loop over
const toFormat = [
  [1, 'one', 'unu'],
  [2, 'two', 'du'],
  [3, 'three', 'tri'],
  [4, 'four', 'kvar']
];

let formatted = "";
for (let i of toFormat) {
  formatted += (i[0] + " (" + i[1] + ")\n");
}
console.log(formatted);

edited Nov 21, 2016 at 20:53

answered Nov 21, 2016 at 20:23

Eli Sadoff

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2 Comments

user663031 Over a year ago

From MDN: It is strongly recommended that assignment operators (+, +=) are used instead of the concat() method.

Eli Sadoff Over a year ago

@torazaburo Thanks for the advice! I did not know. I'll fix my answer to use + instead of concat.

Scott Marcus · Accepted Answer · 2016-11-21 20:23:08Z

0

First, you have omitted the closing quote of the last index in the last array.

But, barring that, the [Array.prototype.forEach()] method can do the trick:

var toFormat = [[1, "one", "unu"], [2, "two", "du"], [3, "three", "tri"], [4, "four", "kvar"]];
  
toFormat.forEach(function(item, index, arry){
    console.log(item[0] + " (" + item[1] + ")");
});

answered Nov 21, 2016 at 20:23

Scott Marcus

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