Parsing return value from one method as two arguments for another function?

Question

I have a function def findSpace(aBookcase): which returns return row,column and another function which takes def setName(self, row, column, name):.

Now, when I execute aBookcase.setName(findSpace(aBookcase), name) I get TypeError: setName() takes exactly 4 arguments (3 given).

How can I make it parse the result from findSpace() as two arguments to function setName(), without changing findSpace(), because I have other code already depend on it

Does setName in a Class?

ling7334
– ling7334

2016-11-22 00:46:02 +00:00
Commented Nov 22, 2016 at 0:46 — ling7334
– ling7334, Commented Nov 22, 2016 at 0:46

TigerhawkT3 · Accepted Answer · 2016-11-22 00:49:38Z

1

findSpace returns a tuple. That is one object. aBookcase.setName expects three separate arguments, in addition to the instance itself. Unpack the result and then use the arguments:

r,c = findSpace(aBookcase)
aBookcase.setName(r, c, name)

In Python 3.5 or higher, you can simply use *:

aBookcase.setName(*findSpace(aBookcase), name)

answered Nov 22, 2016 at 0:49

TigerhawkT3

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