2D python list of numpy arrays to 2D numpy array

Question

Which is the most performant way to convert something like that

problem = [ [np.array([1,2,3]), np.array([4,5])],
            [np.array([6,7,8]), np.array([9,10])]]

into

desired = np.array([[1,2,3,4,5], 
                   [6,7,8,9,10]])

Unfortunately, the final number of columns and rows (and length of subarrays) is not known in advance, as the subarrays are read from a binary file, record by record.

So, the number of elems in each element of the list would be the same, like it's 5 here? — Divakar
– Divakar, Commented Nov 23, 2016 at 9:58
The number for each row is the same, so no padding or else is required. — mneuner
– mneuner, Commented Nov 23, 2016 at 13:11
Then, I guess the fastest one would be with a traditional loop, intialize output array and use np.concatenate iteratively to assign for each row as listed in @Carles Mitjans's solution. — Divakar
– Divakar, Commented Nov 23, 2016 at 15:32
A similar question with answer by Warren: stackoverflow.com/questions/39128514/… — hpaulj
– hpaulj, Commented Nov 23, 2016 at 17:54

Carles Mitjans · Accepted Answer · 2016-11-23 10:00:49Z

5

How about this:

problem = [[np.array([1,2,3]), np.array([4,5])],
        [np.array([6,7,8]), np.array([9,10])]]

print np.array([np.concatenate(x) for x in problem])

edited Nov 23, 2016 at 10:00

answered Nov 23, 2016 at 9:58

Carles Mitjans

4,8663 gold badges22 silver badges39 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

kezzos · Accepted Answer · 2016-11-23 10:49:35Z

2

I think this:

print np.array([np.hstack(i) for i in problem])

Using your example, this runs in 0.00022s, wherease concatenate takes 0.00038s

You can also use apply_along_axis although this runs in 0.00024s:

print np.apply_along_axis(np.hstack, 1, problem)

edited Nov 23, 2016 at 10:49

answered Nov 23, 2016 at 10:40

kezzos

3,2413 gold badges25 silver badges40 bronze badges

6 Comments

mneuner Over a year ago

looks good, but i believe that does it take 2 allocation processes? First for each row, and then every row gets copied into the large array?

hpaulj Over a year ago

Look at bmat code - an hstack for each row, and vstack to join the rows. If the list was flattened, you could use one concatenate and then reshape. I don't think the time differences are significant.

mneuner Over a year ago

np.concatenate seems to be faster than stacking or bmat: problem = [ [np.array([.1]*5000)] * 5 ] * 10000 solution = np.array([np.concatenate(x) for x in problem])

hpaulj Over a year ago

Hstack uses concatenate.

mneuner Over a year ago

maybe, but there'se a clear difference for me (python 3.5, numpy 1.11)

|

Collectives™ on Stack Overflow

2D python list of numpy arrays to 2D numpy array

2 Answers 2

Comments

6 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

6 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related