From the python book:
Learning Python. 5th edition, page #727
I read the following:
if Python finds only a byte code file on the search path and no source, it simply loads the byte code directly; this means you can ship a program as just byte code files and avoid sending source
But when attempting the same on Python 3.5, it doesn't work:
~/Python/Module_Test$ cat a.py
a = "abc"
l = [1,2,3]
importing module 'a' created the byte-code file as:
~/Python/Module_Test/__pycache__$ ls
a.cpython-35.pyc
Now I removed the 'a.py' file and from the byte-code directory, I'm importing the module 'a':
~/Python/Module_Test/__pycache__$ python
Python 3.5.2 |Anaconda 4.2.0 (64-bit)| (default, Jul 2 2016, 17:53:06)
[GCC 4.4.7 20120313 (Red Hat 4.4.7-1)] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> import a
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ImportError: No module named 'a'
I even tried to add the byte-code directory to the search path, still it fails to load the module:
>>> import sys
>>> sys.path.append('/home/pradeep/Python/Module_Test/__pycache__')
>>> import a
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ImportError: No module named 'a'
What I am doing wrong? Can we import module from the byte code without the source? Is my understanding of the statement of the book wrong?